(A) 3x + 2y = -2 (B) 6x - y = 6 (A) + 2(B): 3x + 2y + 12x - 2y = -2 + 12 or 15x = 10 or x = 2/3 substitute this value of x in (A) 2 + 2y = -2 2y = -4 and y = -2 Answer: x = 2/3, y = -2
2y(3x + 1)
3y2 - 2y + 6xy - 4x = y(3y - 2) + 2x(3y - 2) = (y + 2x)*(3y - 2)
3x(2y + 1)
2y + 2xy' + 4y + 4xy' = 0 6y + 6xy' = 0 y' = -y/x
no its not a solution
2y(3x + 1)
3x(2y + 1)
3y2 - 2y + 6xy - 4x = y(3y - 2) + 2x(3y - 2) = (y + 2x)*(3y - 2)
2y + 2xy' + 4y + 4xy' = 0 6y + 6xy' = 0 y' = -y/x
no its not a solution
Both of them are equations!The solution is (x, y) = (2, 1).
1 solution
y = x + 1
(x, y) = (3, 7) is a solution.
x = 3 and y = 2
2y + 3x = 0 2y + -3 = 0 2y = 0 + 3 , 2y = 3 y = 3/2 y = 1.5 x = -1
Since there are no common factors, just multiply everything: 3x times 2y = 6xy