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Q: What is the solution of 3x-4y equals 1 and 6x plus 12y equals 7?

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12y + 5 = 53 12y = 48 y = 4

-6x + 12y = -102 -6x = -12y - 102 x = 2y + 17

12y+2=146 12y=146-2 12y=144 144/12 12x12=144 y=12

12y - 4 = 7y + 165y = 20y = 4

12y = 8x + 24 so y = 2x/3 + 2

12y+3=9y-15 3y=-18 y=-6

6y + 4.. i think

its 10x +9y +1z

12y + 2 or 2*(6y+ 1)

13x - 9y - 10

dont know sorry

3y + 4z + 12y = 3y -3y -3y ------------------------- 4z + 12y = 0 divide everything by 4 z + 3y = 0 -3y -3y z = -3y

negative one and a half

5x=4012y=84124

x = -4y so 3x = -12y Substituting in the second equation, -12y + 2y = 20 or -10y = 20 ie y = -2 And then x = -4y implies that x = 8 Solution: x = 8, y = -2

Answer:12y=132y=132/12=11

6xy +12y = 6y (x+2)

y = 11

12y = 132y = 132/12y = 11

The given equation: =3x-4x plus 9xy-12y =3x-4x+9xy-12y =-x+9xy-12y =-x+3y(3y-4) Answer.

2x + 12 y =36subtract 2x from both sides12y = 36 - 2xdivide both sides by 12y = (36 - 2x)/12

zero solutions. If you plot these two lines, you will see that they are parallel and do not intersect.

5*3y+1+12y-1 = 15y+1+12y-1 = 27y.

5x=11y

-6y + 5 = -67y=12-6y = -72-y = -12y = 12