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What is the set solution 2x-6 -7 equals 7?
2x-6=7, x=?
X2 plus 2x plus -6 equals 0?
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
What is the solution of the equation x2 - 2x - 7?
Without the inclusion of an equality sign the given expression can't be considered to be an equation
X2 plus 3x-7 equals 5x plus 8?
x2 + 3x - 7 = 5x + 8; thus, x2 + 3x - 7 - 5x - 8 = x2 - 2x - 15 = (x - 5)(x + 3) = 0. Therefore the solution is x = 5 or -3.
What is the solution set of the equation 2x-10 plus 7 equals 5?
(2x - 10) + 7 = 52x - 3 = 52x = 8x = 4
What is the set solution 2x-6 -7 equals 7?
2x-6=7, x=?
What is the Factor x2 plus 2x 63?
x2+2x-63 = (x-7)(x+9) when factored
X2 plus 2x plus -6 equals 0?
x2 + 2x -6 = 0 x2 + 2x + 1 = 7 (x + 1)2 = 7 x = -1 ± √7
What is the solution to x2 plus 2x equals 410 the solution is between 7 and 8?
The answer is (3.5)2 plus (4)2 equals 410.
What is the solution of the equation x2 - 2x - 7?
Without the inclusion of an equality sign the given expression can't be considered to be an equation
X2 plus 3x-7 equals 5x plus 8?
x2 + 3x - 7 = 5x + 8; thus, x2 + 3x - 7 - 5x - 8 = x2 - 2x - 15 = (x - 5)(x + 3) = 0. Therefore the solution is x = 5 or -3.
When x3 plus 3x2-2x plus 7 is divided by x plus 1 what is the remainder?
(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)
What is the solution set of the equation 2x-10 plus 7 equals 5?
(2x - 10) + 7 = 52x - 3 = 52x = 8x = 4
How do you solve this trinomial x2-2x-63?
Simplifying x2 + -2x + -63 Reorder the terms: -63 + -2x + x2 Factor a trinomial. (-7 + -1x)(9 + -1x) Final result: (-7 + -1x)(9 + -1x)
When factored what is the solution set of 2x₂-11x-21 equals 0?
7 and (-3/2)
Can you solve x2 plus 2x - 63 equals 0?
x2+2x-63 = 0 When factorised: (x-7)(x+9) = 0 Therefore: x = 7 or x = -9
What is this quadratic equation written in standard form x2 - 10x - 6 equals 2x plus 1?
x2 - 10x - 6 = 2x + 1 Subtracting 2x + 1 from both sides gives: x2 - 12x - 7 = 0
