-x(x2 - 2)(x2 + 3)
Take out the common factor, 3: 3x + 6 = 3(x + 2).
x2-3x+2.25 is the same as 4x2-12x+9 and is (2x-3)(2x-3) when factored
4x2 + 8x + 4 = 4 (x2 + 2x + 1) = 4 (x + 1)2
(x+2)(x2+2x+4)
Simplifying x2 + -2x + -63 Reorder the terms: -63 + -2x + x2 Factor a trinomial. (-7 + -1x)(9 + -1x) Final result: (-7 + -1x)(9 + -1x)
x2 + 2x - 15 = (x + 5)(x - 3)
It can be. x^2 + x + 1 is a factor of 2x^2 + 2x + 2
x2+2x-15 = (x+5)(x-3) when factored
Factor it out: (x+2) squared
-3x3 - 6x2 + 189x = -3x(x2 + 2x - 63) = -3x(x + 9)(x - 7)
(x + 7)(x - 5)
(x + 1)(x + 1)
3(x2 - 2x + 3)
(x + 5)(x - 3)
(x - 1)(x + 3)
x2+2x-63 = 0 When factorised: (x-7)(x+9) = 0 Therefore: x = 7 or x = -9