your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
5-2x3=9
a equals 5
The equation of a vertical line x = 5 or the equation of a horizontal line y = 5.
5 -8
f'(x) = 1/(2x3 + 5) rewrite f'(x) = (2X3 + 5) -1 use the chain rule d/dx (2x3 + 5) - 1 -1 * (2x3 + 5)-2 * 6x2 - 6x2(2x3 + 5) -2 ==================I would leave like this rather than rewriting this
Yes, the equation has a slope of 0.
There is no single coefficient for that equation, as a coefficient is the number by which any term is multiplied. The coefficients in that equation are 5, 2, 4 and 3.
It is a linear equation in x. The equation has the solution x = 0.
Give us the whole equation, and we can help.
Not until it equals something. Equations have equals signs.
-5