2X - 3 = 5
add 3 to each side
2X - 3 + 3 = 5 + 3
2X = 8
divide each side integer by 2
(2/2)X = 8/2
X = 4
--------------check in original equation
2(4) - 3 = 5
8 - 3 = 5
5 = 5
checks
your equation is this... 2x3 + 11x = 6x 2x3 + 5x = 0 x(2x2 + 5) = 0 x = 0 and (5/2)i and -(5/2)i
5-2x3=9
a equals 5
The equation of a vertical line x = 5 or the equation of a horizontal line y = 5.
5 -8
Yes, the equation has a slope of 0.
It is a linear equation in x. The equation has the solution x = 0.
f'(x) = 1/(2x3 + 5) rewrite f'(x) = (2X3 + 5) -1 use the chain rule d/dx (2x3 + 5) - 1 -1 * (2x3 + 5)-2 * 6x2 - 6x2(2x3 + 5) -2 ==================I would leave like this rather than rewriting this
Give us the whole equation, and we can help.
Not until it equals something. Equations have equals signs.
There is no single coefficient for that equation, as a coefficient is the number by which any term is multiplied. The coefficients in that equation are 5, 2, 4 and 3.
-5