Speed = distance/time = 12m/4s = 3m/s
7500 meters per 10 seconds = 750 meters per second = 2,700 km per hour. That's a fast dog.
3 meters per second. enjoy:)
To calculate the velocity of the dog, you divide the distance traveled by the time taken. The dog travels 250 meters east in 8 seconds, so the velocity is 250 meters / 8 seconds = 31.25 meters per second east. Thus, the dog's velocity is 31.25 m/s east.
To find the average speed of the dog, divide the distance traveled by the time taken. The average speed is 100 meters divided by 30 seconds, which equals approximately 3.33 meters per second.
To find the total displacement, we consider the dog’s initial and final positions. The dog runs 80 meters to chase the ball and then returns 80 meters back to its starting point, resulting in no net displacement from that segment. Finally, when the dog runs 20 meters south, the total displacement is 20 meters to the south. Thus, the total displacement is 20 meters south.
To find the speed of the dog, we can use the equation ( s = \frac{d}{t} ), where ( d ) is the distance and ( t ) is the time. In this case, the dog ran 100 meters in 20 seconds. Plugging in the values, the speed ( s ) is ( \frac{100 \text{ meters}}{20 \text{ seconds}} = 5 \text{ meters per second} ).
20 meters
To calculate the average speed of the dog, we use the formula: speed = distance/time. In this case, the distance is 75 meters and the time taken is 5 seconds. Therefore, the average speed of the dog is 75 meters / 5 seconds = 15 meters per second.
To calculate the total displacement of the dog, we consider its starting point as the origin. The dog runs 80 meters north, then returns to its master (which we can assume is at the starting point), and finally runs 20 meters south. Therefore, the total displacement is 80 meters north - 20 meters south, resulting in a net displacement of 60 meters north.
To find the total displacement of the dog, we first note that it runs 80 meters north to chase the ball, then returns 80 meters south to its master, resulting in no net displacement in the north-south direction at that point. After returning to its master, the dog runs south W meters. Therefore, the total displacement is W meters south from the original starting point.
20m
The total displacement of the dog can be calculated using the Pythagorean theorem. After running W meters north and then W meters east, the dog's path forms a right triangle where both legs are W meters. The total displacement is the hypotenuse, which is √(W² + W²) = √(2W²) = W√2. Thus, the total displacement of the dog is W√2 meters in a northeast direction.