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What is the total displacement of a dog that runs north W meters to chase a ball and then runs W meters?
The total displacement of the dog can be calculated using the Pythagorean theorem. After running W meters north and then W meters east, the dog's path forms a right triangle where both legs are W meters. The total displacement is the hypotenuse, which is √(W² + W²) = √(2W²) = W√2. Thus, the total displacement of the dog is W√2 meters in a northeast direction.
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What is the total displacement of a dog that runs north 80 meters to chase a ball returns to its mater and then runs south 20 meters?
20m
What is the total displacement of a dog that runs 80 meters to chase a ball returns to its master and the runs south 20 meters?
To find the total displacement, we consider the dog’s initial and final positions. The dog runs 80 meters to chase the ball and then returns 80 meters back to its starting point, resulting in no net displacement from that segment. Finally, when the dog runs 20 meters south, the total displacement is 20 meters to the south. Thus, the total displacement is 20 meters south.
Mike walks 100 meters north then walks 30 meters south After this he walks another 10 meters north What is the magnitude of his total displacement during this walk in meters?
80
What is a person's total displacement when they walk 20 meters North 40 meters East 50 meters South and 20 meters East?
fu
If a Displacement vectors of 4 km south 2 km north 5 km north combine to a total displacement of?
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
What is the total displacement of a dog that runs north 80 meters to chase a ball returns to its master and then runs south 20 meters?
20 meters
What is the total displacement of a dog that runs north 80 meters to chase a ball returns to its mater and then runs south 20 meters?
20m
What is the total displacement of a dog that runs 80 meters to chase a ball returns to its master and the runs south 20 meters?
To find the total displacement, we consider the dog’s initial and final positions. The dog runs 80 meters to chase the ball and then returns 80 meters back to its starting point, resulting in no net displacement from that segment. Finally, when the dog runs 20 meters south, the total displacement is 20 meters to the south. Thus, the total displacement is 20 meters south.
What is the total displacement of a person that travels 80 meters due South than travels another 50 meters due north?
The total displacement is 30 meters South. Displacement is the difference between the initial and final positions of an object, irrespective of the path taken. In this case, the person returns partially to the initial position after moving North by 50 meters.
A dog walks 6m north 4m south What is the total displcement of the dog from the starting point?
The total displacement of the dog from the starting point can be calculated by finding the net displacement, which is the difference between the distances moved in each direction. In this case, the net displacement would be 6m north - 4m south, resulting in a total displacement of 2m north.
Mike walks 100 meters north then walks 30 meters south After this he walks another 10 meters north What is the magnitude of his total displacement during this walk in meters?
80
What is a person's total displacement when they walk 20 meters North 40 meters East 50 meters South and 20 meters East?
fu
A boy first walks 120 meters north then turns around and walks 120 meters south his total displacement is?
zero
Mike walks 100 meters north then walks 30 meters south. After this he walks another 10 meters north. What is the magnitude of his total displacement during this walk in meters?
The answer is 80 because 100-30+10 is 80.
What situation below that would produce a total displacement of zero?
If a person walks 10 meters north and then walks 10 meters south, their total displacement would be zero since they would end up back where they started.
A dog walks 6m north 4m soutch What is the total displcement of the dog from the starting point?
"Displacement" in physics usually referrs to the net change in position - meaning, take a snapshot of the dog before he starts moving and a snapshot of the dog when he's finished moving, and the distance between his two positions is his net displacement. Nothing he does in between affects the result - only where he starts and where he ends up.If you walk 6 meters north and then turn around and walk 4 meters south, I hope it makes sense that you are now standing 2 meters north of the point where you started. This is your net displacement (2 meters north).
If a Displacement vectors of 4 km south 2 km north 5 km north combine to a total displacement of?
To find the total displacement, we can break it down: the 4 km south and the 2 km north result in a net displacement of 2 km south (4 km south - 2 km north = 2 km south). Then, adding the 5 km north gives a total displacement of 3 km north (2 km south + 5 km north = 3 km north). Therefore, the total displacement is 3 km north.
