umm 0 not difficult
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Linear feet have no width, therefore 277lin.ft = 0 sq ft since 277ft x 0ft = 0 sq ft.
It depends upon what units the 59424.77 have. Assuming it is a unit of area, then to the nearest square mile: 59,424.77 sq miles ≈ 59,425 sq miles 59,424.77 sq km ≈ 22,944 sq miles 59,424.77 ha ≈ 229 sq miles 59,424.77 acres ≈ 93 sq miles 59,424.77 sq m ≈ 0 sq miles 59,424.77 sq yd ≈ 0 sq miles 59,424.77 sq ft ≈ 0 sq miles 59,424.77 sq in ≈ 0 sq miles
A linear length of 1 cm has no width so its area is 1 x 0 = 0 sq cm
first ,let us find the relation between 1 yd sq and 1 ft sq .we get the relation as :1 ft sq= 0 yd sq 1.000 ft sqconverting now ,132 ft sq =14 yd sq 6.00000 ft sq
None.Square metres are a measure of area = length x widthfeet are a measure of length and have a width of 0 (zero).Thus the area of feet = length x 0 = 0.Therefore 900 feet = 0 sq m
Expanded Notation of 371,800 sq km = (3 x 105) + (7 x 104) + (1 x 103) + (8 x 102) + (0 x 101) + (0 x 100) sq km
#include<stdio.h> unsigned sum_row (unsigned* sq, const unsigned width, const unsigned row) { unsigned sum, col; sum = 0; for (col=0; col<width; ++col) sum += sq[row*width+col]; return sum; } unsigned sum_col (unsigned* sq, const unsigned width, const unsigned col) { unsigned sum, row; sum = 0; for (row=0; row<width; ++row) sum += sq[row*width+col]; return sum; } unsigned sum_diag (unsigned* sq, const unsigned width) { unsigned sum, row, col; sum = 0; for (row=0, col=0; row<width; ++row, ++col) sum += sq[row*width+col]; return sum; } unsigned sum_anti (unsigned* sq, const unsigned width) { unsigned sum, row, col; sum = 0; for (row=0, col=width-1; row<width; ++row, --col) sum += sq[row*width+col]; return sum; } bool is_magic (unsigned* sq, const unsigned width) { unsigned magic, row, col; magic = sum_row (sq, width, 0); for (row=1; row<width; ++row) if (magic!=sum_row(sq, width, row)) return false; for (col=0; col<width; ++col) if (magic!=sum_col(sq, width, col)) return false; if (magic!=sum_diag(sq, width)) return false; if (magic!=sum_anti(sq, width)) return false; return true; } int main () { const unsigned width = 3; unsigned a[width][width] {{2,7,6},{9,5,1},{4,3,8}}; unsigned row, col; printf ("Square:\n\n"); for (row=0; row<width; ++row) { for (col=0; col<width; ++col) { printf ("%d ", a[row][col]); } printf ("\n"); } printf ("\n"); if (is_magic((unsigned*)&a, width)) printf ("The square is magic with a magic constant of %d\n", sum_row((unsigned*)&a, 3,0)); else printf ("The square is not magic\n"); return 0; }
0. Do you mean 70 cubic feet? 1 sq yd = 27 cu ft.
45 sq ft
1 meter = 1000 mm so 1 sq meter = 106 sq mm but you would divide. 2 sq mm / 106 = sq m
Using the quadratic equation formula:- x = -3 + sq rt of 22 and x = -3 - sq rt of 22