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Q: What is the sqare root of both sides 4x²-8x plus 4 equals 56?

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No but they are both quadrilaterals because they have 4 sides

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-4x-4 equals -16. Add 4 to both sides; -4x equals -12. Divide both sides by -4; x equals 3.

subtract 15 from both sides then divide both sides by -4. g=12

Add 45 to each side, giving 9x = 45. Divide both sides by 9, giving x = 5

Subtract 9 from both sides: 2x = 15, divide both sides by 2: x = 7.5

4x = 72.divide both sides by 4x = 18

2k - 1 = 0 Add 1 to both sides: 2k = 1 Divide both sides by two: k = 0.5

The = sign

3p - 8 = 13 - 4p : Add 4p to both sides 7p - 8 = 13 : Add 8 to both sides 7p = 21 : Divide both sides by 7 p = 3.

Add 9 to both sides: 7c - 14 Divide both sides by seven: c = 2

26 - x = xAdd 'x' to both sides.26 = 2xDivide both sides by 2.13 = x

2x + 3 = 9x Subtract 2x from both sides: 3 = 7x Divide both sides by 7: 3/7 = x

First you subtract 3x from both sides and get -7=2x+3. Then subtract 3 from both sides and get -10=2x. Then divide both sides by 2 and x=-5.

subtract 5 from both sides 3g=12 divide both sides by 3 g=4

aN - bN = a - bN : add bN to both sides then aN = a : divide both sides by a N = a/a = 1

+0.05 and -0.05 both are.

If you divide both sides by -7.82, you get x=.6048

3x + 4x = 847x = 84divide both sides by 7x = 12

Subtract 4 from both sides and add y to both sides. This would give you 2y=14. Then, divide both sides by 2. y=7.

3x+7=19 3x=12 minus 7 from both sides x=4 divide by three on both sides leaving just what x equals

A

you add 4 to both sides (2x-4 and 16) to cancel out the 4 and get 2x=20. then you divide both sides by 2.

Add one to both sides to get 3x = 21 Then divide both sides by three to get x = 7