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Solve Cos x - 1 equals 0?
cos x - 1 = 0 cos(x) = 1 x = 0 +/- k*pi radians where k = 1,2,3,...
What is the value of k if 5k - 7 equals -7?
To find the value of k, you need to isolate k on one side of the equation. Start by adding 7 to both sides of the equation to get 5k = 0. Then, divide both sides by 5 to solve for k. Therefore, the value of k is 0.
Factor the expression 2 k squared minus k minus 4 equals 0?
2 k^2 - k - 4 = 0 2 (k^2 - (1/2)k - 2) = 0 2 ((k - 1/4)^2 - 1/16 - 2) = 0 2 ((k - 1/4)^2 - 33/16) = 0 2 (k - 1/4 - sqrt(33)/4)(k - 1/4 + sqrt(33)/4) = 0 32 (4k - 1 - sqrt(33))(4k - 1 + sqrt(33)) = 0
Why is k the y-intercept in y equals k x?
The y-intecept is where the graph of the equation crosses the y-axis. In other words, it occurs where x=0. For y=kx, the y-intercept is 0, not k. Substitute 0 for x, and y=0. In an equation of the form y=ax+b, then the y-intercept is b, and the x-intercept is -b/a.
Given that a is the root of each of the equations xsquare-5x plus k equals 0 and xsquare-6x plus 3k equals 0 where k is not equal to 0 find k and a?
Since a is the root of both equations, a satisfies them:a2 - 5a + k = 0a2 - 6a + 3k = 0The right hand side of both the equations are same. Therefore,a2 - 5a + k = a2 - 6a + 3k6a - 5a = 3k - ka = 2kk = (a/2)Substituting k = a/2 in one of the equations,a2 - 5a + (a/2) = 0Solving, a=9/2k=a/2=9/4Thus 'a' = (9/2) and 'k' = (9/4).
