cos x - 1 = 0 cos(x) = 1 x = 0 +/- k*pi radians where k = 1,2,3,...
To find the value of k, you need to isolate k on one side of the equation. Start by adding 7 to both sides of the equation to get 5k = 0. Then, divide both sides by 5 to solve for k. Therefore, the value of k is 0.
2 k^2 - k - 4 = 0 2 (k^2 - (1/2)k - 2) = 0 2 ((k - 1/4)^2 - 1/16 - 2) = 0 2 ((k - 1/4)^2 - 33/16) = 0 2 (k - 1/4 - sqrt(33)/4)(k - 1/4 + sqrt(33)/4) = 0 32 (4k - 1 - sqrt(33))(4k - 1 + sqrt(33)) = 0
The y-intecept is where the graph of the equation crosses the y-axis. In other words, it occurs where x=0. For y=kx, the y-intercept is 0, not k. Substitute 0 for x, and y=0. In an equation of the form y=ax+b, then the y-intercept is b, and the x-intercept is -b/a.
Since a is the root of both equations, a satisfies them:a2 - 5a + k = 0a2 - 6a + 3k = 0The right hand side of both the equations are same. Therefore,a2 - 5a + k = a2 - 6a + 3k6a - 5a = 3k - ka = 2kk = (a/2)Substituting k = a/2 in one of the equations,a2 - 5a + (a/2) = 0Solving, a=9/2k=a/2=9/4Thus 'a' = (9/2) and 'k' = (9/4).
K j equals j when K is 1 or j is 0.
If you're talking about (K-0)=1, then the answer is most definitely 1.
It is -273.15 deg C.
0
cos x - 1 = 0 cos(x) = 1 x = 0 +/- k*pi radians where k = 1,2,3,...
k = -3; factors are (9x + 3)(x - 1)
For the equation x2- 10x - k equals 0, you can solve this by knowing that if there is only one solution then the discriminant b2 - 4ac must be equal to 0. In this equation, a is 1, b is 10 and c is k This equation becomes 100 - 4k equals 0, and k is 25.
x = 16.7+180*k deg where k is an integer.
a = 4.0 i - 3.0 j + 1.0 k b = -1.0 i + 1.0 j + 4.0 k → a + b = (4.0 + -1.0) i + (-3.0 + 1.0) j + (1.0 + 4.0) k = 3.0 i - 2.0 j + 5.0 k → a - b = (4.0 - -1.0) i + (-3.0 - 1.0) j + (1.0 - 4.0) k = 5.0 i - 4.0 j - 3.0 k → a - b + c = 0 → c = -(a - b) = -5.0 i + 4.0 j + 3.0 k So that a - b + c = (5.0 - 5.0) i + (-4.0 + 4.0) j + (-3.0 + 3.0) k = 0 i + 0 j + 0 k = 0.
If the line y = kx - 2 is a tangent to the curve y = x² - 8x + 7, then where they meet: kx - 2 = x² - 8x + 7 → x² - (8+k)x + 9 = 0 will have a repeated root, ie the determinant is zero: (8+k)² - 4 ×1 × 9 = 0 → 64 + 16k + k² - 36 = 0 → k² + 16k + 28 = 0 → (k + 2)(k + 14) = 0 → k = -2 or -14.
If: 6x^2 +2x +k = 0 has equal roots Then using the discriminant of b^2 -4ab=0: 4 -24k=0 => k=-4/-24 => k=1/6 Therefore the value of k = 1/6
To find the value of k, you need to isolate k on one side of the equation. Start by adding 7 to both sides of the equation to get 5k = 0. Then, divide both sides by 5 to solve for k. Therefore, the value of k is 0.