The square root of -16 is 4 i
256 has two square roots: 16 and -16.
There are no real square roots of -256. But using complex numbers the square roots of -256 are 16i and -16i.
The square root of -16 is: 4 i
x=16
It is: 4 or -4
As for example the square root of 16 is 4 because 4*4 = 16
16 is an even number from 10 to 20, and its square roots are -4 and +4.
A positive number has two square roots, its principal (positive) root and its negative root. This is because a negative number multiplied by a negative number equals a positive number. In this instance, the square roots of 256 are 16 and -16.
16*sqrt(3) * 4*sqrt(2) = 16*4*sqrt(3)*sqrt(2) = 64*sqrt(6)
√(16/81) = (√16)/(√81) = 4/9 → The two roots are 4/9 and -4/9
It's not. Take 49 and 16 for example. The square root of the sum is the square root of 65. The sum of the square roots is 11.
The positive square root of 256 is 16 because 16 multiplied by 16 equals 256. The negative square root of 256 is -16 because -16 multiplied by -16 also equals 256. In general, for any positive number x, the square roots of x are both a positive and a negative number, with the positive square root being the principal square root.