2 + 3 + 4 = 9
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-3 + 4 + (-2) = 1 + (-2) = 1 - 2 = -1.
Sum = -5 - 3 - 2 + 14 = 4 Count = 4 So mean = Sum/Count = 4/4 = 1
To solve the expression, first calculate the product of 3 and the sum of 4 and -2. The sum of 4 and -2 is 2, and multiplying that by 3 gives 6. Now, divide 8 by this product: (8 \div 6 = \frac{4}{3}) or approximately 1.33.
A sum of 4 is more likely. Out of the 36 possible outcomes with a pair of 6-sided dice, only one will have a sum of 2 {1-1}. Three of the possibilities sum to 4. {1-3, 2-2, 3-1}
-2
6 4 3 does not equal 2. The sum of 6, 4, and 3 is 13, not 2.
10, unless they are non collinear vectors.
The number is 4 (4+3) * (4+3) = 49 (4+2) * (4+2) = 36 49 - 36 = 13
2/3 + 4/6 = 4/3 or 11/3
The question is ambiguous.Does it want the sum of the squares, or the square of the sum ? They're different.Here are both:1). Sum of the squares: . (1)2 + (2)2 + (3)2 + (4)2 + (5)2 = 1 + 4 + 9 + 16 + 25 = 552). Square of the sum: . (1 + 2 + 3 + 4 + 5 )2 = (15)2 = 225
3(2+4) 3(6) 18 ■
I am a 3 digit number divisible by 7 but not 2 the sum of my digits is 4 what number am I