96.
The sum of 3,268 and 96 is 3,364.
The sum of 39 and -96 is -57.
31 + 32 + 33 = 96
The total sum is 96
96
94+95+96 96
491.
31+32+33 = 96
If three consecutive integers have the sum of 96, then the problem can be expressed with the equation... N + (N+1) + (N+2) = 96 ...Simplify that and solve and you get... 3N + 3 = 96 3N = 93 N = 31 ... so the three integers are 31, 32, and 33.
31, 32, 33
31, 32, 33
The numbers are -33, -32, and -31.