96.
The sum of 3,268 and 96 is 3,364.
The sum of 39 and -96 is -57.
31 + 32 + 33 = 96
The total sum is 96
94+95+96 96
96
491.
31+32+33 = 96
If three consecutive integers have the sum of 96, then the problem can be expressed with the equation... N + (N+1) + (N+2) = 96 ...Simplify that and solve and you get... 3N + 3 = 96 3N = 93 N = 31 ... so the three integers are 31, 32, and 33.
First, we find the greatest common factor (GCF) of 15 and 81, which is 3. The sum of 15 and 81 is 96. Therefore, the product of the GCF and the sum is 3 multiplied by 96, which equals 288. Thus, the final answer is 288.
-8 × (number + 21) = 96 → number + 21 = 96 ÷ -8 → number = 96 ÷ -8 - 21 = -12 - 21 = -33
31, 32, 33