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Q: What is the sum of 9 and the quotient of x and 7?

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It is x/9 - 7.

x / 7 = 9x = 63

think about it. x+9=(-7) reverse the equation. (-7)-9=x

the quotient of 7 and x is simply 7x, unless you know what x stands for

9

x/(-7) or -x/7

That's the same as 7/9 x 10/9 = 70/81

28 + 35 = (4 x 7) + (5 x 7) = 9 x 7 = 63

x-7

(x/7)2 x= quotient of a number 7= the denominator of x 2 = represents squared

9/x

If the number is x, then 7/x.

If x/3 = 9, then x = 27.

x/9

You can't have the sum of one thing. Factors multiply to get a product. 7 x 9 = 63. If you add those two numbers, you will get a sum. 7 + 9 = 16

That's probably "quotient." 9 x 2 - 14/7 = 18 - 2 = 16

10

ur mom

The quotient is a result of division. So it is x/7 or 7/x depending on how the numbers are being divided.

x/7

Since 7 and 9 are relatively prime, any number that is a multiple of both is a multiple of 7 x 9 = 63. There are 9 multiples of 63 less than or equal to 600, so this can be computed directly using Sum = 63(1 + 2 + ... + 9) which simplifies to Sum = 63 x 9 x (1 + 9)/2 from the formula for arithmetic series. Most programming languages have a built-in function which returns the quotient and the remainder when dividing integers, or you can write your own. So to generalize, denote 600 by max, 7 by a, and 9 by b. Input those values first. Suppose quotient returns the quotient of an integer division. begin N <- quotient(max, lcm(a,b)) (* N is the number of multiples of both a and b <= max *) sum <- lcm(a,b) * N * (1 + N)/2 (* Use the formula *) end This is the most efficient solution. There are other solutions that don't assume an understanding of arithmetic series. Specifically, you could write: begin i <- 1; sum <- 0 (* Initialize counter to 1 and sum to 0 *) While i <= max/lcm(a,b) do sum <- sum + i * lcm(a,b) i++; od end

5, 7, 95 + 7 + 9 = 215 x 7 x 9 = 315

0.7778

x(9+x)

It is the equation: x/9 + 7 = 5