7 & 9
7 + 9 = 16
7 X 9 = 63
'Product' is another way of saying 'multiply the two numbers together'.
9 times 7=63 A simpler answer is 1 times 63!
The numbers are 62 and 63.
63 and 64
The numbers are 21 and 63.
To find two numbers whose sum is 16 and product is 63, we can set up the equations ( x + y = 16 ) and ( xy = 63 ). By substituting ( y = 16 - x ) into the product equation, we get ( x(16 - x) = 63 ), which simplifies to ( x^2 - 16x + 63 = 0 ). Solving this quadratic equation, we find the numbers are 7 and 9, as ( 7 + 9 = 16 ) and ( 7 \times 9 = 63 ).
The two numbers would be 7 and 9. 7 times 9 = 63 7 + 9 = 16
'Product' is another way of saying 'multiply the two numbers together'.
You can't have the sum of one thing. Factors multiply to get a product. 7 x 9 = 63. If you add those two numbers, you will get a sum. 7 + 9 = 16
7+9=16 7x9=63 63-16 = 47
First, we need to clarify the condition in the problem: the sum of two numbers is 16, and the difference between the two numbers is 6. Based on these conditions, we can say that these two numbers are respectively x and y. According to the problem description, we can list the following equations: The sum of the two numbers is 16, which is x plus y is equal to 16. The difference between the two numbers is 6, which is 6 x−y=6. By solving this system of equations, we get x=9 and y=7. So the product of these two numbers is 9 x 7 = 63
any combination of numbers that add up to 63
The sum of 36 plus 63 can be expressed as a product by first calculating the sum, which is 99. This can be factored and expressed as a product of its prime factors: (99 = 9 \times 11), or as (3^2 \times 11). Thus, the expression for the sum of 36 and 63 as a product is (9 \times 11).
xy=63 x +y = 16 y = 16-x x(16-x) = 63 16x -x^2 -63 = 0 x^2 -16x+63 = 0 (x-9)(x-7) = 0 x = 9 y = 7
3 (21+5)
63
19 + 21 + 23 = 63