Best Answer

That's probably "quotient."

9 x 2 - 14/7 = 18 - 2 = 16

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Q: What does double 9 and then subtract the quiescent of 14 and 7?

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2*(-7) = -14

7/8 = 21/24 7/12 = 14/24 21/24 - 14/24 = 7/24

Double the last digit and subtract the last digit from the remaining digits.

9y subtract 11 equals 7

You can determine if a number is divisible by 7 by using the following method: E.g. 161 - Double the last digit (2 x 1 = 2) Subtract 2 from the number formed by the the remaining digits in this case, 16 -2 = 14 If the result is divisible by 7 (14 /7 =2); then the original number is divisible by 7. 161 / 7 = 23

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Double the last digit. Subtract it from the rest. If the result is divisible by 7, the original number is divisible by 7.

13

10/14 - 9/14 = 1/14

(w + 2)(w - 7)

2*(-7) = -14

Get a common denominator (14), so you have (10 6/14 ) - (5 7/14). Since 7/14 > 6/14, borrow a 1 from the 10:1 = 14/14, so you have (9 20/14) - (5 7/14). Subtract the fractions and subtract the whole numbers: 413/14

7/8 = 21/24 7/12 = 14/24 21/24 - 14/24 = 7/24

9x + 7 - 2x = 14 Combine like terms: 7x + 7 = 14 Subtract 7 from both sides: 7x = 7 Divide both sides by 7: x = 1

5/7 - 7/14 becomes: 10/14 - 7/14. Then subtract across to get the final answer: 3/14. 5/7 became 10/14 by finding the lowest common denominator which is 14. Then you figure 7 goes into 14 two times, and 2x5 = 10 therefore 5/7 becomes 10/14.

Double the last digit and subtract the last digit from the remaining digits.

Double the last digit, subtract it from the rest. If the result is divisible by 7, the whole number is divisible by 7.

If you double the last digit and subtract it from the rest of the number and the answer is zero or divisible by 7, then the whole number is divisible by 7.