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sum = ½ × number of numbers × (first number + last number)

= ½ × (3003 - 1002 + 1) × (1002 + 3003)

= ½ × 2002 × 4005

= 4,009,005

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โˆ™ 2018-03-18 07:01:19
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Q: What is the sum of all numbers between 1002 and 3003 inclusive?
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