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More answers

sum = ½ × number of numbers × (first number + last number)

= ½ × (3003 - 1002 + 1) × (1002 + 3003)

= ½ × 2002 × 4005

= 4,009,005

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Wiki User

7y ago
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4009005

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Fiona Morshed

Lvl 2
2y ago
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Q: What is the sum of all the numbers between 1002 and 3003 inclusive?
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