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first you find the first term which is multiple of 7 which is 7
then you find the last term which is multiple of 7 is 1295
then we find n (number of terms) from the formula
Un=U1+(n-1)d
Un= last term,U1= first term,n= number of terms,d=the difference between a term and the term after it which in this case is 7
1295=7+(n-1)7
1295= 7+7n-7
1295=7n
185=n
now we have every value we need so we apply them in the formula
Sn=n/2(U1+Un) "this formula can be applied only in arithmetic sequence"
=185/2(7+1295)
= 120435
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∙ 6y ago
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