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The sum of all multiples of 3 below 500 is the sum of 3 + 6 + ... + 498 = 41583

The sum of all multiples of 5 below 500 is the sum of 5 + 10 + ... + 495 = 24750

Depending upon the interpretation of "of 3 and 5", the answer is one of:

  1. The sum of all multiples of both 3 and 5 below 500 is the sum of 15 + 30 + ... + 495 = 8415
  2. The sum of all multiples of 3 below 500 and all multiples of 5 below 500 is 41583 + 24750 = 66333
  3. Since the multiples of both 3 and 5 (that is 15, 30, ...) have been counted twice - once in the multiples of 3 and once in the multiples of 5 - the sum of all multiples of 3 or 5 or both below 500 is 41583 + 24750 - 8415 = 57918

I have emphasised the word below with regard to 500 since 500 is a multiple of 5, but 500 is not below (less than) itself, that is the multiples are of the numbers 1, 2, 3, ..., 499. If the question was intended to mean less than or equal to 500, add an extra 500 to the multiples of 5 above, making the sum of the multiples of 5 be 25250 and the final sums (1) 8415, (2) 66833, (3) 58418.

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Q: What is the sum of all the multiples of 3 and 5 below 500?
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What is the sum of all the odd numbers up to 500?

The sum of the first 500 odd numbers is 250,000.


Find the sum of all the multiples of 3 or 5 below 1000?

Well, you could add them one by one, or write a small computer program to do that, but here is a shortcut:Use the formula for an arithmetic series, to find the sum of all the multiples of 3 (3, 6, ... 999).Similarly for all the multiples of 5 (5, 10, ... 995).Add it all up.Multiples of 15 will be counted twice in his calculation, so you'll have to calculate the sum of all the multiples of 15, and subtract it from the above.Well, you could add them one by one, or write a small computer program to do that, but here is a shortcut:Use the formula for an arithmetic series, to find the sum of all the multiples of 3 (3, 6, ... 999).Similarly for all the multiples of 5 (5, 10, ... 995).Add it all up.Multiples of 15 will be counted twice in his calculation, so you'll have to calculate the sum of all the multiples of 15, and subtract it from the above.Well, you could add them one by one, or write a small computer program to do that, but here is a shortcut:Use the formula for an arithmetic series, to find the sum of all the multiples of 3 (3, 6, ... 999).Similarly for all the multiples of 5 (5, 10, ... 995).Add it all up.Multiples of 15 will be counted twice in his calculation, so you'll have to calculate the sum of all the multiples of 15, and subtract it from the above.Well, you could add them one by one, or write a small computer program to do that, but here is a shortcut:Use the formula for an arithmetic series, to find the sum of all the multiples of 3 (3, 6, ... 999).Similarly for all the multiples of 5 (5, 10, ... 995).Add it all up.Multiples of 15 will be counted twice in his calculation, so you'll have to calculate the sum of all the multiples of 15, and subtract it from the above.


What is the sum of all 2-digit multiples of 5?

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Related questions

The sum of all the multiples of 3 or 5 below 1000?

The multiple of 3 nearest to and below 1000 is 999. 999/3 = 333 The sum of all the multiples is 3 x 333 x 334/2 = 166833 The multiple of 5 nearest to and below 1000 is 995. 995/5 = 199 The sum of all the multiples is 5 x 199 x 200/2 = 99500


What is the sum of the first 500 multiples of 3?

Created in a spreadsheet, the answer is: 375750


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There are infinitely many multiples of 9 and it is not possible to add them all.


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What is the Sum of the positive non-multiples of three that are less than 1000?

That would be equal to the sum of all positive integers less than 1000 minus the sum of all positive multiples of three that are less than 1000. That would be equal to: (1000 + 1) * (1000 / 2) - 3 * (333 + 1) * (333 / 2) = 1001 * 500 - 1000 * 166.5 = 500500 - 166500 = 334000


What is the sum of all the odd numbers up to 500?

The sum of the first 500 odd numbers is 250,000.


Find the sum of all the multiples of 3 or 5 below 1000?

Well, you could add them one by one, or write a small computer program to do that, but here is a shortcut:Use the formula for an arithmetic series, to find the sum of all the multiples of 3 (3, 6, ... 999).Similarly for all the multiples of 5 (5, 10, ... 995).Add it all up.Multiples of 15 will be counted twice in his calculation, so you'll have to calculate the sum of all the multiples of 15, and subtract it from the above.Well, you could add them one by one, or write a small computer program to do that, but here is a shortcut:Use the formula for an arithmetic series, to find the sum of all the multiples of 3 (3, 6, ... 999).Similarly for all the multiples of 5 (5, 10, ... 995).Add it all up.Multiples of 15 will be counted twice in his calculation, so you'll have to calculate the sum of all the multiples of 15, and subtract it from the above.Well, you could add them one by one, or write a small computer program to do that, but here is a shortcut:Use the formula for an arithmetic series, to find the sum of all the multiples of 3 (3, 6, ... 999).Similarly for all the multiples of 5 (5, 10, ... 995).Add it all up.Multiples of 15 will be counted twice in his calculation, so you'll have to calculate the sum of all the multiples of 15, and subtract it from the above.Well, you could add them one by one, or write a small computer program to do that, but here is a shortcut:Use the formula for an arithmetic series, to find the sum of all the multiples of 3 (3, 6, ... 999).Similarly for all the multiples of 5 (5, 10, ... 995).Add it all up.Multiples of 15 will be counted twice in his calculation, so you'll have to calculate the sum of all the multiples of 15, and subtract it from the above.


What is the sum of all 2-digit multiples of 5?

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The sum of three consecutive multiples of 6 is 666find the multiples?

The sum of three consecutive multiples of 6 is 666, the multiples are 216, 222 and 228.


Is 95 the sum of integers between 1 and 500?

No. The sum of all integers between 1 and 500 is 124,749.


What number is a multiple of 6 and 12 and has the sum of 9 numbers?

All multiples of 12 are also multiples of 6 and they all can be written as the sum of nine numbers.


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