to find the numbers between two numbers use this formula and reblace the a with the smaller number and b with the larger number
((b^2+b)/2-b)-((a^2+a)/2)
so the answer is 135 not including 20 as part of the sum
The sum is 75.
The answer is 28
The sum of the five odd numbers between 10 and 20 is: sum = 5 x (11 + 19) / 2 = 75.
The composite numbers in that range are 10, 12, 14, 15, 16, 18, 20. I don't know if you're including 10 and 20 or not. Add them up however you like.
It is 0.5
The sum is 75.
The sum of -5 and 20 is 15. The distance between -5 and 20 is 25. The sum of the numbers between -5 and 20 is 180. The sum of the numbers from -5 to 20 is 195.
well, let's break it down. First, the even numbers between 1 and 11 are, 2,4,6,8,10. Now 2+4=6, 6+6=12, 8+12=20, 20+10=30. So, to answer your question simply, the sum of even numbers between 1 and 11, is 30.
The answer is 28
The sum of the five odd numbers between 10 and 20 is: sum = 5 x (11 + 19) / 2 = 75.
-20
The composite numbers in that range are 10, 12, 14, 15, 16, 18, 20. I don't know if you're including 10 and 20 or not. Add them up however you like.
It is 0.5
The numbers are 30 and 20.
20 number
The sum of two numbers between 20-40 is 58. The difference is 12
Avreage = Sum/number of values So 10 = sum/2 Multiply both sides by 2: 20 = sum