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(5-8)+(1-11) 5-8+1-11 6-19 -13

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Q: What is the sum of the complex numbers 5-8 plus 1-11?
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Related questions

What is the sum of 111 plus 444?

111 + 444 = 555


Find three consecutive numbers that have a sum of 111?

36 + 37 + 38 = 111


What are three consecutive numbers whose sum is 111?

The numbers are 36, 37 and 38.


What are three consecutive numbers with a sum of 111?

36, 37, 38 36+37+38=111


What 3 prime numbers have the sum of 111?

31, 37, and 43


What is the sum of three consecutive odd numbers that equal 111?

35,37,39


What are all of the numbers that are odd three digit numbers with a digit sum of 3?

111 and 201


Find two numbers whose sum is 111 and difference is 25?

The two numbers are 43 and 68. 43 + 68 = 111, while 68 - 43 = 25


If the sum of four numbers is 444 what is the average of the four numbers?

111 is the average, as you would divide 444 by 4.


The sum of two complex numbers is always a complex number?

A "complex number" is a number of the form a+bi, where a and b are both real numbers and i is the principal square root of -1. Since b can be equal to 0, you see that the real numbers are a subset of the complex numbers. Similarly, since a can be zero, the imaginary numbers are a subset of the complex numbers. So let's take two complex numbers: a+bi and c+di (where a, b, c, and d are real). We add them together and we get: (a+c) + (b+d)i The sum of two real numbers is always real, so a+c is a real number and b+d is a real number, so the sum of two complex numbers is a complex number. What you may really be wondering is whether the sum of two non-real complex numbers can ever be a real number. The answer is yes: (3+2i) + (5-2i) = 8. In fact, the complex numbers form an algebraic field. The sum, difference, product, and quotient of any two complex numbers (except division by 0) is a complex number (keeping in mind the special case that both real and imaginary numbers are a subset of the complex numbers).


How many digits might be in the sum of two 3 digit numbers?

three (111 + 111 = 222) or four (999 + 999 = 1998)


What are three consecutive odd integers whose sum is 111?

The numbers are 35, 37 and 39.