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Q: What is the sum of the complex numbers 5-8 plus 1-11?

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The numbers are 36, 37 and 38.

35,37,39

111 is the average, as you would divide 444 by 4.

three (111 + 111 = 222) or four (999 + 999 = 1998)

The numbers are 35, 37 and 39.

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111 + 444 = 555

36 + 37 + 38 = 111

The numbers are 36, 37 and 38.

36, 37, 38 36+37+38=111

31, 37, and 43

35,37,39

111 and 201

The two numbers are 43 and 68. 43 + 68 = 111, while 68 - 43 = 25

111 is the average, as you would divide 444 by 4.

A "complex number" is a number of the form a+bi, where a and b are both real numbers and i is the principal square root of -1. Since b can be equal to 0, you see that the real numbers are a subset of the complex numbers. Similarly, since a can be zero, the imaginary numbers are a subset of the complex numbers. So let's take two complex numbers: a+bi and c+di (where a, b, c, and d are real). We add them together and we get: (a+c) + (b+d)i The sum of two real numbers is always real, so a+c is a real number and b+d is a real number, so the sum of two complex numbers is a complex number. What you may really be wondering is whether the sum of two non-real complex numbers can ever be a real number. The answer is yes: (3+2i) + (5-2i) = 8. In fact, the complex numbers form an algebraic field. The sum, difference, product, and quotient of any two complex numbers (except division by 0) is a complex number (keeping in mind the special case that both real and imaginary numbers are a subset of the complex numbers).

three (111 + 111 = 222) or four (999 + 999 = 1998)

The numbers are 35, 37 and 39.