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Q: What is the sum of the complex numbers 5-8 plus 1-11?

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111 + 444 = 555

36 + 37 + 38 = 111

111 and 201

The numbers are 36, 37 and 38.

A "complex number" is a number of the form a+bi, where a and b are both real numbers and i is the principal square root of -1. Since b can be equal to 0, you see that the real numbers are a subset of the complex numbers. Similarly, since a can be zero, the imaginary numbers are a subset of the complex numbers. So let's take two complex numbers: a+bi and c+di (where a, b, c, and d are real). We add them together and we get: (a+c) + (b+d)i The sum of two real numbers is always real, so a+c is a real number and b+d is a real number, so the sum of two complex numbers is a complex number. What you may really be wondering is whether the sum of two non-real complex numbers can ever be a real number. The answer is yes: (3+2i) + (5-2i) = 8. In fact, the complex numbers form an algebraic field. The sum, difference, product, and quotient of any two complex numbers (except division by 0) is a complex number (keeping in mind the special case that both real and imaginary numbers are a subset of the complex numbers).

35,37,39

31, 37, and 43

36, 37, 38 36+37+38=111

The two numbers are 43 and 68. 43 + 68 = 111, while 68 - 43 = 25

111 is the average, as you would divide 444 by 4.

three (111 + 111 = 222) or four (999 + 999 = 1998)

Count how many of the numbers are odd. If an odd number of them are odd, then their sum is odd. If an even number of them are odd, then their sum is even.

The numbers are 35, 37 and 39.

According to Wolfram Alpha, (1/2) (9 plus or minus i times the square root of 39) Since these numbers are complex, it means there is no solution with real numbers for this problem.

The sum of 74 plus 6 is a total of 80. Sum is the result you get when adding two numbers together.

average is 113 so 111, 113 and 115

Impossible. They are all odd numbers. The sum of 5 odd numbers is also an odd number and cannot therefore total 50.

DR of sum = DR(1+2+3+4) = DR(10) = 1

The question is equivalent to asking if there are two numbers whose sum is 6 (the coefficient of x) and whose product is 18 (the constant term). Since there are no such real numbers, the answer is NO. There is a solution in the complex domain but the normal context for such questions is the real numbers.

The absolute value of the sum of two complex numbers is less than or equal to the sum of their absolute values.

The set of numbers given are not suited for this since 9 and 35 are co-prime so that the GCF of the given set of numbers is 1. Using a GCF of 1 does not help.

It is 1000110.

int i, sum = 0; for (i=0; i<20; i+=2) sum+=i;

sum = a + b + c;

The sum of the numbers given is 31. 1 + 2 + 4 + 8 + ... + 2n = 2n+1 - 1