Yes.
2x3 - 11x2 + 12x + 9
= (x - 3)(2x2 - 5x - 3)
= (x - 3)(2x2 - 6x + x - 3)
= (x - 3)(2x + 1)(x - 3)
= (2x + 1)(x - 3)2
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x(x + 4)(x - 3)
(x + 5)(x^2 + 2x + 2)
x^(3) - 12x^(2) + 35 x Factor out 'x' Hence x(x^(2) - 12x + 35) Factor the quadratic x(x - 5)(x - 7) Done!!!!!
Since that isn't an equation, there is really nothing to solve.
Factor out an X X(X^2 - 12X + 35) factor quadratic equation X(X - 7)(X - 5) ------------------- fully factored