(18-2)*180 = 2880 degrees
The sum of interior angle ( Sum-of-interior-angles-n-gon) of n-gon is:If we have a ,Then
The sum of the interior angles of an n-gon is found by the formula: (n-2)*(180) degrees. So a 38-gon would have (38-2)*(180) degree sum for its interior angles, which equals 6,480 degrees.
The sum of the interior angles is 6480 degrees.
The interior angles of an 11-gon add up to 1620 degrees
4140 degrees
Sum of exterior angles: 360 degrees Sum of interior angles: 2160
5,760 degrees
4000 degrees
1620 degrees
5940 degrees
The sum of the interior angles of an n-gon is (n-2)*180 degrees. So, for a 40-gon, the sum of the interior angles would be 38*180 = 6840 degrees. If the 40-gon was not regular that is as far as you could go. But if it was a regular n-gon, then all its interior angles are equal, and each would be of 6840/40 = 171 degrees.
The interior angles add up to 3960 degrees