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What is the sum of the digits of 330?
The digits of 330 are 3, 3 and 0, so the sum of those digits means add them up - 3+3+0=6
Is 6618 divisible 3 6 and 9?
Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)
Is 1 trillion 17 a prime number?
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
How many positive integers from 1 to 1000 inclusive are there such that is a multiple of 3 and the digit sum of is also a multiple of 3?
All multiples of 3 have digits that add up to a multiple of 3. There are 333 multiples of 3 between 1 and 1000.
How many 3 digits whole numbers whose sum is 3?
There are no 3-digit whole numbers whose digits sum to 3. The smallest 3-digit number is 100, and the largest is 999, but in neither case is the sum of the digits equal to 3.
How many permutations of 3 different digits are there chosen from the ten digits 0 to 9 inclusive?
How many permutations of 3 different digits are there, chosen from the ten digits 0 to 9 inclusive?
What is the sum of the digits of 330?
The digits of 330 are 3, 3 and 0, so the sum of those digits means add them up - 3+3+0=6
A number is divisible by 3 if the blank is divisible by 3?
A number is divisible by 3 if the sum of its digits is divisible by 3.
Is 6618 divisible 3 6 and 9?
Yes, yes, and no. 3- sum of digits must be multiple of 3. 6- sum of digits must be multiple of 3 and number must be even (multiple of 2). 9- sum of digits must be multiple of 9. (The sum of the digits here is 21.)
Is 1 trillion 17 a prime number?
Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.Since the sum of the digits is divisible by 3, the original number is also divisible by 3.
How many positive integers from 1 to 1000 inclusive are there such that is a multiple of 3 and the digit sum of is also a multiple of 3?
All multiples of 3 have digits that add up to a multiple of 3. There are 333 multiples of 3 between 1 and 1000.
How many 3 digits whole numbers whose sum is 3?
There are no 3-digit whole numbers whose digits sum to 3. The smallest 3-digit number is 100, and the largest is 999, but in neither case is the sum of the digits equal to 3.
How are the divisibility rules for 3 6 and 9 alike?
A number is divisible by 3 if the sum of its digits is a multiple of 3. A number is divisible by 6 if the sum of its digits is a multiple of 3 and it's even. A number is divisible by 9 if the sum of its digits is a multiple of 9.
Indentify the conclusion what conditional a number is divisible by 3 if the sum of the digits of the number is divisible by 3?
If the sum of the digits of a number is divisible by 3, then the number is divisible by 3.
What is the sum of the digits in one dozen?
A dozen is equal to 12. The sum of the digits of 12 are 1 + 2 = 3.
Determine if a number is divisible by 3?
Check the sum of the digits, if the sum divisible by 3 then the number is divisible by 3. Example 910: the sum of digits= 9 + 1 + 0 = 10, but 10 is not divisible by 3, so the number 910 is not divisible by 3. Example 2154: the sum of digits = 2 + 1 + 5 + 4 = 12, this sum is divisible by 3, so the number 2154 is divisible by 3. if the sum is long you can check the sum of the sum and apply the same rule. Example 52498731: the sum of digits = 5 + 2 + 4 + 9 + 8 + 7 + 3 + 1 = 39, the sum of the digits for 39 = 3 + 9 = 12, so the original number, i.e. 52498731 is divisible by 3.
What 3 digit number ia 3 times the sum of its digits?
Without digging too deeply into this question, we can see immediately that it has no solution. -- The largest possible sum of 3 digits is (9 + 9 + 9) = 27 -- 3 times (the largest possible sum of 3 digits) is (3 x 27) = 81 -- 3 times the largest possible sum of 3 digits is smaller than any 3-digit number.
