Top Answer

1 + 1 = 2

The sum of the digits is therefore 2.

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It you add up all the digit in the number they will total 11. For example the number 425 has digits that sum to 11. (4 + 2 + 5 = 11)

65

65 has 13 as a factor because 13 divides into 65 evenly with no remainder. The sum of the digits of 65 is 11 because 6 + 5 = 11

65

what number is prime to 40 29 - it's a prime number (divisible only by 1 and itself) and if you sum the two digits 2 + 9 = 11

How about 65 because 6+5 = 11

11

The number 1111115

By the sum of its digits: 10. By each of its individual digits: 11.

83

12

11

No integer fits those conditions.

Add together all the digits in the odd positions in the number. Sum = A Add together all the digits in the even positions in the number. Sum = B If A-B is 0 or if it divisible by 11 (positive or negative), then the original number is divisible by 11.

65

65

56

38

83 A+

the sum of my digits is 6? answer=60

the number is 83. 8+3=11 83-38=45

56

That would be 29.

83 8+3=11 83-38=45

the sum of individual digits of a given integer number