The sum of the first eleven positive odd integers is 121.
The sum of the first 30 positive integers is: 465.
The sum of the first ten positive integers is: 55
The sum of the first 60 positive integers is 1830.
The formula for the first n positive numbers is n x (n+1)/2, so for n=11 the sum is 11 x 12 /2 = 66
The sum of the first 200 positive integers is 19,900.
The sum of the first 500 positive integers is: 125,250
The first odd positive integers are "1" and "3" which the sum is 4.
The first four positive integers of 13 are : 26, 39, 52, 65
The sum of the first 40 even positive integers can be equal to 820.
The sum of the first 40 positive integers (1-40) is: 820
The sum of the first 5,000 odd, positive integers is 5,000 squared or 25,000,000.
The sum of the first 230 positive, odd integers is 230 squared or 52,900.
The sum of the first 2,006 positive, odd integers is 4,024,036.
The sum of the first thousand even, positive integers is 1,001,000.
The sum of the squares of the first 1000 positive odd integers (from 12 to 19992) is 1333333000.
The sum of the first positive odd integers less than 101 is 10,000.
Yes. The sum of the first 5,000 odd, positive integers is 25,000,000 (25 million).
The sum of the first 201 positive integers is 20100 if you include 0 (i.e. from 0 to 200). If you sum the integers from 1 to 201 instead, the sum is 20301.
The sum of the first seven positive INTEGERS is 28. The sum of the fisrt seven positive numbers is infinitesimally small.
I assume that we are speaking entirely of positive integers. There are six divisors of 228 that are less than 15: 1, 2, 3, 4, 6, and 12. There are six divisors of 228, greater than 15: 19, 38, 57, 76, 114, and 228 itself. There are several convenient ways to check that you have got them all, without the labour of dividing the first 228 integers into 228. One way is the following: Note, first, that 228 = 19 X 12 = 19 X 3 X 2 X 2. We may call that its 'prime factorisation'. Because every positive integer can be factorised into positive prime integers in only one way, we may safely conclude that every positive divisor of 228 must contain 19, either once or not at all; similarly, it must contain 3 once or not at all; and it must contain 2, twice, once, or not at all. That allows 2 X 2 X 3 = 12 choices for a divisor of 228; hence, there must be twelve divisors of 228, including, of course, 1 and 228 itself. Now, half of these divisors must be less than the square-root of 228, which is just a little bit more than 15; half must be more than 15. 228 is not a perfect square, so we may conclude that six divisors are less than 15. They are easy to identify, since their divisors, in turn, must contain some combination of 1's, 2's and 3's. The remaining six divisors, greater than 15, can be found by dividing the first six divisors into 228. And the job is done. If you want negative divisors, simply take the negatives of all the twelve positive divisors. canislunis
The first three positive integers, 1, 2, and 3, satisfy this condition.
Quotient positive: Both integers have the same sign: both positive or both negative. Quotient zero: The first integer is 0. Quotient negative: The integers have opposite signs: one positive and one negative.