The formula for the first n positive numbers is n x (n+1)/2, so for n=11 the sum is 11 x 12 /2 = 66
The sum of the first three even positive integers is 2 + 4 + 6 = 12.
-21
Multiplying integers involves combining two or more whole numbers to find their total as a repeated addition. For example, multiplying 3 by 4 means adding 3 a total of 4 times (3 + 3 + 3 + 3), resulting in 12. The product of two integers can be positive or negative, depending on the signs of the integers involved: multiplying two positive or two negative integers results in a positive product, while multiplying one positive and one negative integer results in a negative product.
The positive integers from 1 to 100 are the whole numbers starting from 1 and ending at 100. This includes every integer in between, specifically: 1, 2, 3, 4, ..., 98, 99, and 100. In total, there are 100 positive integers in this range.
The mean of the first 100 integers can be calculated by finding the sum of these integers and dividing by the total count. The sum of the first 100 integers (from 1 to 100) is ( \frac{100(100 + 1)}{2} = 5050 ). Dividing this by 100 gives a mean of ( \frac{5050}{100} = 50.5 ). Therefore, the mean of the first 100 integers is 50.5.
They total 650. * * * * * It is 2550.
The positive integers up to 4 are: 1, 2, 3, and 4. This is a total of four positive integers.
The sum of the first three even positive integers is 2 + 4 + 6 = 12.
-21
Multiplying integers involves combining two or more whole numbers to find their total as a repeated addition. For example, multiplying 3 by 4 means adding 3 a total of 4 times (3 + 3 + 3 + 3), resulting in 12. The product of two integers can be positive or negative, depending on the signs of the integers involved: multiplying two positive or two negative integers results in a positive product, while multiplying one positive and one negative integer results in a negative product.
The positive integers from 1 to 100 are the whole numbers starting from 1 and ending at 100. This includes every integer in between, specifically: 1, 2, 3, 4, ..., 98, 99, and 100. In total, there are 100 positive integers in this range.
The mean of the first 100 integers can be calculated by finding the sum of these integers and dividing by the total count. The sum of the first 100 integers (from 1 to 100) is ( \frac{100(100 + 1)}{2} = 5050 ). Dividing this by 100 gives a mean of ( \frac{5050}{100} = 50.5 ). Therefore, the mean of the first 100 integers is 50.5.
900 This explains it. A positive integer is a palindrome if it reads the same forward and backwards such as 1287821 and 4554. Determine the number of 5-digit positive integers which are NOT palindromes. We start by counting the total number of 5 digit positive integers. The first digit is between 1 and 9, so we have 9 choices. Each of the other 4 digits can be anything at all (10 choices for each). This gives us 9(10)4 = 90000 five-digit positive integers. Now we need to count the number of 5 digit palindromes. Again, we have 9 choices for the first digit and 10 choices for each of the next two. The tens and units digits however are fixed by our choices so far. Therefore, there are only 900 five-digit palindromes. Therefore, the total number of five-digit positive integers which are not palindromes is 90000-900 = 89100.
To determine the number of ways to write a sum that equals 23, we need to consider how many distinct integers or combinations of integers can be added together to reach that total. The number of ways can vary significantly depending on the restrictions placed on the integers (e.g., positive integers, negative integers, or allowing repetitions). Without specific constraints, there are infinitely many combinations, such as using different positive integers that add up to 23, or including negative integers. If the context is more specific, such as using a fixed number of addends or only positive integers, the answer would require further details.
Combine them together, using the rules of priority (PEMDAS or BIDMAS).
If a number is at least 5, and ends in "5" or "0", then it is divisible by 5. To further elaborate, If we are speaking of all numbers, the answer is an infinite number. If we limit it to positive integers, the answer is 50, 45, 40, 35, 30, 25, 20, 15, 10, 5, 0. Eleven total since 0 is a positive number.
The first ten positive numbers total 55.