1,001,000
Interpreting this question as the arithmetic series
2+4+6+8...+1,998+2,000
and using the formula
Sn = n/2 [a1+an],
we get
S1,000 = 1,000/2 (2+2,000) = 1,001,000
The sum of the first thousand even, positive integers is 1,001,000.
10100.
They are: 0, 2, 4, 6, 8 and 10
First six even positive integers.
The sum of the first three even positive integers is 2 + 4 + 6 = 12.
The sum of the first thousand even, positive integers is 1,001,000.
The sum of the first 40 even positive integers can be equal to 820.
2, 4, 6, 8, ... continue adding 2 at a time, up to 2000.
405
10100.
They total 650. * * * * * It is 2550.
30*62 = 1860
50%
The sum of the squares of two consecutive positive even integers is 340. Find the integers.
First six even positive integers.
They are: 0, 2, 4, 6, 8 and 10
The sum of the first three even positive integers is 2 + 4 + 6 = 12.