10100.
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(7*100*101)/2 = 35,350 jpacs * * * * * What? How can there be 35,350 integers in the first 100 integers? There are 14 of them.
Should be 50! Every odd integer is 1 less than the corresponding even integer and there are 50 of each in 100...
There are 25 of them.
there are 999 - 100 + 1 = 900 positive triple digit positive integers, between 100 and 999.(e.g. there are 102 - 100 + 1 = 3 triple digit integers between 100 and 102,namely 100, 101 and 102.)multiply that by 2 to take in consideration of the negative integers,you have 1800 triple digit integers.
Of the 729 numbers that satisfy the requirement of positive integers, 104 are divisible by 7.