The sum of the squares of two consecutive positive even integers is 340. Find the integers.
Sn = n*(n+1)
The sum of the first n positive integers (i.e. 1+2+3+...+n) is given by n(n+1)/2 so the sum of the first 25 positive integers is 1+2+3+...+25 = 25x26/2 = 325. The sum of the first 25 EVEN numbers will be double this i.e. 2+4+6+...+50 = 650.
The sum of the first seven positive INTEGERS is 28. The sum of the fisrt seven positive numbers is infinitesimally small.
105625
The sum of the first thousand even, positive integers is 1,001,000.
The sum of the first 40 even positive integers can be equal to 820.
10100.
The sum of the first ten positive integers is: 55
The sum of the first 500 positive integers is: 125,250
The sum of the first 30 positive integers is: 465.
The sum of the first 60 positive integers is 1830.
The sum of the first 200 positive integers is 19,900.
The sum of the first eleven positive odd integers is 121.
The sum of the first 2,006 positive, odd integers is 4,024,036.
The first odd positive integers are "1" and "3" which the sum is 4.
30*62 = 1860