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Q: What is the sum of the measure of the exterior angle of any polygon?

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The largest exterior angle measure is 120o. It is the exterior measure of an equilateral triangle (which is a regular polygon).

The sum of the exterior angle of any polygon is 360. So divide that by 8 in this case and each exterior angle has measure 360/8 or 45 degrees.

Any irregular polygon can have an exterior angle measuring 60 degrees.Any irregular polygon can have an exterior angle measuring 60 degrees.Any irregular polygon can have an exterior angle measuring 60 degrees.Any irregular polygon can have an exterior angle measuring 60 degrees.

The sum of the exterior angles of any polygon is 360 degrees.

Exterior angle of ANY regular n-sided polygon is 360/n degrees...

For any polygon: 180-interior angle = exterior angle and the exterior angles of any polygon add up to 360 degrees

The sum of the exterior angle of ANY polygon is 360 degrees.

If the question is: If the exterior angle of a regular polygon is 45 degrees, how many sides does the polygon have? then the answer is:the sum of the exterior angles of any convex polygon is 360so 360/45 = 8

Exterior angle of ANY regular n-sided polygon is 360/n degrees, in this case 360/12 ie 30o

Total exterior angles of any polygon = 360 deg. In this case there are 6 exterior angles, so each angle is 60 deg.

90 degrees. Exterior angle of any regular n-sided polygon is 360/n degrees

For any polygon, regular or otherwise, the sum of exterior angles is always 3600.

The exterior angles of any polygon add up to 360. 360/8 = 45

There is no such polygon because the interior angle plus the exterior angle of any polygon adds up to 180 degrees because there are 180 degrees on a straight line

There can be no such polygon. The sum of the exterior angles of ANY polygon is 360 degrees. If it is a regular polygon, then the number of angles MUST divide 360 degrees. Since 18.95 does not divide 360, there cannot be such a polygon. If the exterior angle was 18.94737... degrees, it would be a 19-sided polygon.

The sum of the exterior angles of any polygon must be 360 degrees.360/8 = 45 degrees

A polygon with any number of sides can have an exterior angle that is larger than the corresponding interior angle. However, a triangle is the only regular polygon where the exterior angle is larger.

There is no term to calculate any angle of any irregular polygon. For a regular polygon with n sides, each exterior angle is 360/n degrees. Each interior angle is (180 - exterior angle).

The sum total of all exterior angles of any polygon is 360 degrees. So if you're given thevalue of one exterior angle AND THE POLYGON IS REGULAR(all exterior angles are thesame size), all you have to do is divide the size of one angle into 360, and the quotientis the number of sides.

The exterior angle of this 'polygon' would be 180 - 130 = 50 Now the sum of the exterior angles of any polygon is 360 degrees, so the number of sides would be supposedly: = 360/50 = 7.2 Now since a polygon cannot have 7.2 sides, a regular polygon's angle can't measure 130 degrees.

The regular polygon whose exterior angle measure is 12 degrees, has 30 sides (360/12, since the exterior angles on any polygon always add up to 360 degrees).

Exterior angle of any regular n-sided polygon is 360/n degrees, in this case n = 5 so 72o

The sum of the exterior angles of any polygon is 360 degrees. If the polygon is regular then each exterior angle is 360 divided by the number of sides, so in this case each angle will be 10 degrees.

equal to 180°

The sum of the exterior angles in any polygon is 360 degrees.Therefore that polygon is a decagon.