28
The numbers needed are 1 and 7
six, seven 7 + 6 = 13 (sum) 7 - 6 = 1 (difference) 7 x 6 = 42 (product)
1, 4 and 7
To find the sum of the products of two different whole numbers that equal 7, we can identify the pairs of whole numbers whose product is 7. The pairs are (1, 7) and (7, 1), as well as (7, 1) and (1, 7) again. The product of each pair is 7, and since they are the same, the sum of these products remains 7. Therefore, the answer is 7.
Numbers that have a product of 8 are 1,8 and 2,4. Their sums are 9 and 6 respectively. Numbers that have a product of 7 and a sum of 8 are 1 and 7.
7 meadowood
7 and 7
The sum of the prime numbers from 1 to 12 is equal to 2 + 3 + 5 + 7 + 11 = 28.
6 and 7
If by "smaller than ten" you mean closer to zero than 10, then sum = -9 + -7 + ... + -1 + 1 + ... + 7 + 9 = 0 If you mean the numbers less than 10, then: sum = 9 + 7 + ... + 1 + -1 + -3 + ... = -∞ If you mean the counting numbers less than 10, then: sum = 1 + 3 + 5 + 7 + 9 = ½ × 5 × (1 + 9) = ½ × 5 × 10 = 25
Finding the sum of numbers means adding them. So: 6 + 1 =7 The sum of six and one is seven.
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25