To find the sum of the products of two different whole numbers that equal 7, we can identify the pairs of whole numbers whose product is 7. The pairs are (1, 7) and (7, 1), as well as (7, 1) and (1, 7) again. The product of each pair is 7, and since they are the same, the sum of these products remains 7. Therefore, the answer is 7.
Not possible in whole numbers
12 and 3.
7 and 8
6 and 4
34 and 36
the product of 3 whole numbers is 5. Their sum is 7. what are the numbers
Not possible in whole numbers
Not whole numbers, no.
For the product to be zero, one of the numbers must be 0. So the question is to find the maximum sum for fifteen consecutive whole numbers, INCLUDING 0. This is clearly achived by the numbers 0 to 14 (inclusive), whose sum is 105.
They are 12 and 15
The numbers are 13 and 8 The product is 104
12 and 3.
6 and 4
They are 9 and 5
7 and 8
272 is the maximum possible.
168.