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The surface area would be (h x (b/2)) x 4 + b2

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Q: What is the surface area of a square pyramid with the height of 6.2 and base of 5.4?
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Related questions

What is the surface area of the right square pyramid in square meters?

It depends on the dimensions of the base and the height (slant or vertical) of the pyramid.


What is the surface area of a square pyramid when 4 is the side length and 13 as the slant height?

120


The pyramid shown has a square base that is 1818 inches on each side. The slant height is 1616 inches. What is the surface area of the pyramid?

It is 9180900 square inches.


What is the surface area of a square pyramid?

It is the lateral area (which is 1/2 the perimeter multiplied by the slant height), plus the area of the base.


What is the lateral area and surface area of a regular square pyramid?

Lateral area: Twice the side of the square times the slant height. Surface area: The side of the square squared plus twice the side of the square times the slant height. a=side of square b=slant height L.A.=2(ab) S.A.=(a)(a)+(2(ab))


What is the surface area of a pyramid with area of the base 20 slant height 7 and perimeter of the base 30?

It is 125 square units.


What is the lateral surface area of this square pyramid that has a base length of 4 centimeters and a slant height of 9 centimeters?

72 cm square.


What is the area of a square pyramid?

The answer will depend on the area of the base, whether or not it is a right pyramid, and its height.


How do you find the perpendicular height of a square based pyramid?

To find the perpendicular height of a square pyramid, first compute for the volume of the pyramid. Then divide the volume by the area of the base to find pyramid's height.


What is the total surface area of a square pyramid with an apothem of 8 and a height of 8.54 and the squares length and width of 6?

138.48


What is the surface area of a square pyramid of 9cm and 6cm?

The surface area of a square pyramid depends on the lengths of the sides of the square base and of the vertical height. While the question does give two linear measures, it does not say which is which! And without that crucial bit of information, I cannot provide a more useful answer.


What is the slant height of a pyramid that has all sides as equilateral triangles with sides of length of 9 cm and the surface area of the pyramid is 140.4 square cm?

The surface area of the pyramid is superfluous to calculating the slant height as the slant height is the height of the triangular side of the pyramid which can be worked out using Pythagoras on the side lengths of the equilateral triangle: side² = height² + (½side)² → height² = side² - ¼side² → height² = (1 - ¼)side² → height² = ¾side² → height = (√3)/2 side → slant height = (√3)/2 × 9cm = 4.5 × √3 cm ≈ 7.8 cm. ---------------------------- However, the surface area can be used as a check: 140.4 cm² ÷ (½ × 9 cm × 7.8 cm) = 140.4 cm² ÷ 35.1 cm² = 4 So the pyramid comprises 4 equilateral triangles - one for the base and 3 for the sides; it is a tetrahedron.