The surface area would be (h x (b/2)) x 4 + b2
It is the lateral area (which is 1/2 the perimeter multiplied by the slant height), plus the area of the base.
Lateral area: Twice the side of the square times the slant height. Surface area: The side of the square squared plus twice the side of the square times the slant height. a=side of square b=slant height L.A.=2(ab) S.A.=(a)(a)+(2(ab))
The answer will depend on the area of the base, whether or not it is a right pyramid, and its height.
The surface area of a square pyramid depends on the lengths of the sides of the square base and of the vertical height. While the question does give two linear measures, it does not say which is which! And without that crucial bit of information, I cannot provide a more useful answer.
144
It depends on the dimensions of the base and the height (slant or vertical) of the pyramid.
120
It is 9180900 square inches.
It is the lateral area (which is 1/2 the perimeter multiplied by the slant height), plus the area of the base.
Lateral area: Twice the side of the square times the slant height. Surface area: The side of the square squared plus twice the side of the square times the slant height. a=side of square b=slant height L.A.=2(ab) S.A.=(a)(a)+(2(ab))
It is 125 square units.
72 cm square.
The answer will depend on the area of the base, whether or not it is a right pyramid, and its height.
To find the perpendicular height of a square pyramid, first compute for the volume of the pyramid. Then divide the volume by the area of the base to find pyramid's height.
138.48
The surface area of a square pyramid depends on the lengths of the sides of the square base and of the vertical height. While the question does give two linear measures, it does not say which is which! And without that crucial bit of information, I cannot provide a more useful answer.
The surface area of the pyramid is superfluous to calculating the slant height as the slant height is the height of the triangular side of the pyramid which can be worked out using Pythagoras on the side lengths of the equilateral triangle: side² = height² + (½side)² → height² = side² - ¼side² → height² = (1 - ¼)side² → height² = ¾side² → height = (√3)/2 side → slant height = (√3)/2 × 9cm = 4.5 × √3 cm ≈ 7.8 cm. ---------------------------- However, the surface area can be used as a check: 140.4 cm² ÷ (½ × 9 cm × 7.8 cm) = 140.4 cm² ÷ 35.1 cm² = 4 So the pyramid comprises 4 equilateral triangles - one for the base and 3 for the sides; it is a tetrahedron.