answersLogoWhite

0


Want this question answered?

Be notified when an answer is posted

Add your answer:

Earn +20 pts
Q: What is the total mass of rn 222 remaining in an original 160 mg sample of rn 222 after 19.1 days?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Math & Arithmetic

How many days remaining from February 5 2008 up to July 15 2008?

121 days


How many days are in august and how many days are in September?

There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.


How much of radioactive substance remains after 15 hours if it's half life is 5 hours?

The half-life of a radioactive substance is the time that it takes for half of the atoms to decay. With a half-life of 10 days, half has decayed in this time. After 20 days, a further 10 days/another half life, a further half of the remainder has decayed, so 1/4 of the original material remains, 1/4 of 15g is 3.75 grams. This is the amount of original radioactive substance remaining, but it’s daughter isotope ( what the decay has produced ) is also present, so the original sample mass is effectively constant, especially in a sealed container. Even in an unsealed container, and assuming alpha ( helium nucleii) emission, a drop in mass per radioactive atom of 4 Atomic Mass units, compared with the original atom of, say 200 amu is only 2% mass decrease, less for heavier decaying nucleii.


Why does March have 5 weeks?

There are 31 days in March. March in 2015 only has four full weeks of 7 days, with 3 days remaining.


How long is 30 days in weeks?

4 weeks and 2 days. 30 divided by 7 equals 4 with 2 remaining.

Related questions

What is the total mass of 222Rn remaining in an original 160-milligram sample of 222Rn after 19.1 days?

5.0 mg is the total mass of 222Rn remaining in an original 160-milligram sample of 222Rn after 19.1 days.


How long will it take for a 12.0-g sample of iodine-131 to decay to leave a total of 1.50 g of the isotope The half-life of iodine-131 is 8.07 days?

half life is 8.1 days, so it takes 8.1 days for half the iodine sample to decay. It takes another 8.1 days for half of the remaining sample (ie. 1/4th of the original sample) to decay. So it takes 16.2 days for 3/4th of the sample to decay.


A sample of radioactive isotope has a halflife of 1 day how much of the original sample will be left at the end of the fourth day?

If a sample of radioactive material has a half-life of one week the original sample will have 50 percent of the original left at the end of the second week. The third week would be 25 percent of the sample. The fourth week would be 12.5 percent of the original sample.


The half-life of radon-222 is about four days. After how many days is the amount of radon-222 equal to one-sixteenth of its original amount?

Let's step through the half-life of radon to see how it works. Radon-222 starts at full strength. In four days (its half-life), it is at half strength. In four more days, it is again at half strength (of the half strength) for a total of 1/4 strength. In four more days, it is again half the strength (of the 1/4 strength) for a total of 1/8 strength. In four more days, it is another half life weaker, for a total of 1/16 strength. In 16 days, this isotope of radon has just 1/16th the original radiation.


How much of an 80-milligram sample of Iodine-131 would be left after 32 days?

Iodine 131 is radioactive and has a half life of about 8 days. After 32 days there would be approximately 5 milligrams remaining


Determine the amount of time it takes for three fourths of a radioactive sample of an isotope to decay?

The half-life is 4 days. That means half of it will be gone in 4 days, and that leaves half of the original sample. In another 4 days, half of the remaining half will have decayed. And that will leave only 1/4 th of the original sample. That means 3/4 ths of the original sample will have decayed. In 8 days, three fourths of a sample of a radioactive element with a half-life of 4 days will have decayed.


What is the half life of a radioactive isotope if it takes 6.2 days for a 72 gram sample to decay to 18grams?

18 grams are one fourth of the original sample mass of 72 grams. Accordingly, the half life is 6.2/4 = 1.55 days.


Bismuth 210 has half life of 5 days and a sample originally has a mass of 800mg What is the formula for mass remaining after t days?

The mass can be determined with the formula m=800(.5)^(t/5)


How big is a sampler mascara bottle?

Sample means a smaller portion of the original product, therefore a sample mascara bottle will be pretty small, probably lasting you 1-3 days max.


During an experiment a solution containing 24 mg of phosphorus 32 was preparedHow much of the isotope will remain after 28 days if its half-life is 14 days?

Your sample of phosphorous will literally half itself every 14 days. So after 14 days there is 12mg left. After 28 days, there is 6mg remaining.


The half life of Rn-222 is 4 daysWhat was the original mass of a sample of this isotope remains after 21 hrs?

The half-life on 222Rn86 is 3.8235 days. A sample of this isotope will decay to 0.8533 of its original mass after 21 hours. AT = A0 2(-T/H) AT = (1) 2(-21/(24*3.8235)) AT = 0.8533


Howmany days remaining to world cup?

13 days