Want this question answered?
121 days
There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.There are 31 days in August and there are 30 days in September, which is a total of 61 days.
The half-life of a radioactive substance is the time that it takes for half of the atoms to decay. With a half-life of 10 days, half has decayed in this time. After 20 days, a further 10 days/another half life, a further half of the remainder has decayed, so 1/4 of the original material remains, 1/4 of 15g is 3.75 grams. This is the amount of original radioactive substance remaining, but it’s daughter isotope ( what the decay has produced ) is also present, so the original sample mass is effectively constant, especially in a sealed container. Even in an unsealed container, and assuming alpha ( helium nucleii) emission, a drop in mass per radioactive atom of 4 Atomic Mass units, compared with the original atom of, say 200 amu is only 2% mass decrease, less for heavier decaying nucleii.
There are 31 days in March. March in 2015 only has four full weeks of 7 days, with 3 days remaining.
4 weeks and 2 days. 30 divided by 7 equals 4 with 2 remaining.
5.0 mg is the total mass of 222Rn remaining in an original 160-milligram sample of 222Rn after 19.1 days.
half life is 8.1 days, so it takes 8.1 days for half the iodine sample to decay. It takes another 8.1 days for half of the remaining sample (ie. 1/4th of the original sample) to decay. So it takes 16.2 days for 3/4th of the sample to decay.
If a sample of radioactive material has a half-life of one week the original sample will have 50 percent of the original left at the end of the second week. The third week would be 25 percent of the sample. The fourth week would be 12.5 percent of the original sample.
Let's step through the half-life of radon to see how it works. Radon-222 starts at full strength. In four days (its half-life), it is at half strength. In four more days, it is again at half strength (of the half strength) for a total of 1/4 strength. In four more days, it is again half the strength (of the 1/4 strength) for a total of 1/8 strength. In four more days, it is another half life weaker, for a total of 1/16 strength. In 16 days, this isotope of radon has just 1/16th the original radiation.
Iodine 131 is radioactive and has a half life of about 8 days. After 32 days there would be approximately 5 milligrams remaining
The half-life is 4 days. That means half of it will be gone in 4 days, and that leaves half of the original sample. In another 4 days, half of the remaining half will have decayed. And that will leave only 1/4 th of the original sample. That means 3/4 ths of the original sample will have decayed. In 8 days, three fourths of a sample of a radioactive element with a half-life of 4 days will have decayed.
18 grams are one fourth of the original sample mass of 72 grams. Accordingly, the half life is 6.2/4 = 1.55 days.
The mass can be determined with the formula m=800(.5)^(t/5)
Sample means a smaller portion of the original product, therefore a sample mascara bottle will be pretty small, probably lasting you 1-3 days max.
Your sample of phosphorous will literally half itself every 14 days. So after 14 days there is 12mg left. After 28 days, there is 6mg remaining.
The half-life on 222Rn86 is 3.8235 days. A sample of this isotope will decay to 0.8533 of its original mass after 21 hours. AT = A0 2(-T/H) AT = (1) 2(-21/(24*3.8235)) AT = 0.8533
13 days