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A 12.2-g sample of x reacts with sample of y to form 78.9g of xy what is the mass of y that reacted?
-66.7
The specific heat of lead is 128 kg degrees Celsius How much heat is needed to raise the temperature of a 0.015kg sample of lead by 10 degrees Celsius?
The relevant equation behind this problem is Q=m*c* ΔT Where Q is the energy that must be added to or taken from the system, m is the mass of the object, c is the objects specific heat, and ΔT is the change in temperature in Celsius or Kelvin. Plugging in the given values we get that Q=.015kg * 128J/(kg*C) * 10C=19.2J. Therefore, you need 19.2 joules of heat in order to raise the temperature of a .015kg sample of lead by 10 degrees Celsius.
Sample promissory note How do you combine my balance to the next enrollment?
To combine your balance with the next enrollment, you typically need to inform the institution about your intention to carry over the outstanding balance. They may require you to sign a new promissory note or agreement outlining the terms of the combined balance. Ensure you review any fees or interest that may apply and confirm the process with the school's financial office for accurate guidance.
Why is the equivalence point important when doing a titration calculation?
The equivalence point in a titration is crucial because it indicates the exact moment when the amount of titrant added is stoichiometrically equivalent to the amount of analyte in the sample. At this point, the reaction is complete, allowing for accurate determination of the concentration of the unknown solution. Identifying the equivalence point ensures that calculations based on volume and molarity yield precise results, facilitating proper analysis and interpretation of data in chemical experiments.
What is the specific heat of a substance that absorbs 2.5 x 10 joules of heat when a sample of 1.0 x 10 g of the substance increased in temperature from 10.0c to 70.0 degree c?
Q (heat) = mass*Specific Heat*Temperature differenceI assume 2.5 * 101 Joules? or 25 J & 10 grams of substance?25 J = 10 grams * (SH) * (70-10oC)25 J =10 g *60oC * SHSH = 25 J/(10 g * 60oC)S.H. = 0.0417 J/gOC
How many grams and moles are in Bismuth?
Depends on how much of the sample there is.
How could you tell the difference between cobalt 60 a sample of radon 222 and a sample of bismuth 83?
Cobalt-60 has two gamma photopeaks at 1.17 MeV and 1.33 MeV. Radon-222 is an alpha emitter. Bismuth-83 is not a valid isotope. 83 is the atomic number of bismuth, but you need to know the atomic mass number. The nuclide with the longest half-life is bismuth-208, and it decays by beta+ decay.
How long will it take a g sample of bismuth to decay such that 2.0 g of the element remains?
You forgot to say that isotope is.
How many atom of a 1.0 mole sample of bismuth 214 will remain after 20 minutes?
All radio active reactions are of first order reactions , for those first order reactions rate constant , k = 0.693 / t 1/2 : t 1/2 = half life of Bi is = 19.7 min So k = 0.693 / 19.7 = 0.0352 min -1 For a first order reaction rate constant , K = ( 2.303/t)x log (a / ( a-x) ) Where a = initial atoms = 6.023x10 23 atom / mol a-x = atoms left after time t = ? t = time = 20 min Plug the values we get log (a / ( a-x) = kt / 2.303 = ( 0.0352x20 ) / 2.303 = 0.305 a / (a-x) = 10 0.305 = 2.02 (a-x) = (6.023x10 23 ) / 2.02 = 2.98 x 10 23 atoms
What is the total mass of 222Rn remaining in an original 160-milligram sample of 222Rn after 19.1 days?
To find the remaining mass of a radioactive isotope after a certain time, you can use the radioactive decay formula: [M_{\text{final}} = M_{\text{initial}} \times \left( \frac{1}{2} \right)^{\frac{t}{t_{1/2}}}] Given that the half-life of (^{222}\text{Rn}) is 3.8 days, and the initial mass is 160 milligrams, you can substitute these values into the formula to find the final mass.
What is the formula for calculating the mean of a sample, represented by the symbol "" in statistics?
The formula for calculating the mean of a sample, represented by the symbol "" in statistics, is to add up all the values in the sample and then divide by the total number of values in the sample. This can be written as: x / n, where x represents the sum of all values in the sample and n is the total number of values in the sample.
What is the formula in finding the margin of error in slovins formula if the sample size and the population is given?
yes
What is the significance about the equilibrium between bismuth chloride and bismuth oxychloride?
The following is an experiment which can be carried out in a laboratory.ReagentsSolid bismuth chlorideConcentrated hydrochloric acidMethodologyTake approximately 1 gram of bismuth chloride to a test tube. And then add around 2 mL of water into it. Now, add the concentrated hydrochloric acid drop-wise till the solid dissolves.Next add excess water till a white suspension is formed.Then get a sample from the suspension and add the concentrated hydrochloric acid drop-wise.Follow the steps 2 and 3 alternately.The white suspension is formed by bismuth oxychloride.Addition of dilute acid will not give the proper results as it results in a lack of the concentration of chloride ions.
How do you calculate density using a formula?
Density of a substance = (mass of a sample of the substance) divided by (volume of the same sample)
Which formula is used for sample mean?
=AVERAGE(A1:A34)
What is the half life of a radioisotope if a 100g sample becomes 25g after 18 years?
The half-life of the radioisotope is 9 years. This is calculated by determining the time it took for half of the original sample to decay. Since the sample went from 100g to 25g in 18 years, it lost 75g in that time period. After the first half-life, the sample would have 50g remaining, and after the second half-life, it would have 25g remaining.
How can one determine the number of moles in a given sample?
To determine the number of moles in a given sample, you can use the formula: moles mass of sample (in grams) / molar mass of the substance. This formula helps you calculate the amount of substance in terms of moles based on its mass and molar mass.
