The total number of alphabets is 26. So the probability of letter C = No of time c is present in the alphabets / Total number of alphabets So probability of letter c is 1/26
No
C=cost x=cans C=70x
int matrix[][]; // the matrix to find the max in int max = matrix[0][0]; int r,c; for(r = 0; r < 3; ++r) { for(c = 0; c < 3; ++c) { if(matrix[r][c] > max) { max = matrix[r][c]; } } } // max is now the maximum number in matrix
First the 'values' of the GPA system:A = 4 pointsB = 3 pointsC = 2 pointsD = 1 pointF = 0 pointsSo, add the sum of the points and divide by the total number of entries. So In this particular question: 3 x 2 = 6 (for the 3 C's) + 4 + 3 + 1 + 0.So ... 6+4+3+1+0 = 14. Now divide that by the total entries (7) and you get 2, or a C grade average.
C-3
The total number of alphabets is 26. So the probability of letter C = No of time c is present in the alphabets / Total number of alphabets So probability of letter c is 1/26
If B and C are the components of the mixture the total number of molecules is identical.
No
Oxidation number of C is +3. Oxidation number of O is -2.
Total students in class = C Number of boys = Z Number of girls = C-Z Total stamps distributed = (3xZ) + [(C-Z)x5] = 3Z + 5C - 5Z = 5C - 2Z
The answer is this: c/5=3 c=15
there is 8 Na-1 C-2 H-3 O-2
5 atoms totally: 1 lithium (Li), 1 carbon (C) and 3 oxygen (O)
C=cost x=cans C=70x
c=16h
+3