The total number of alphabets is 26.
So the probability of letter C = No of time c is present in the alphabets / Total number of alphabets
So probability of letter c is 1/26
The word "space" consists of 5 letters: s, p, a, c, and e. If you are choosing one letter at random from these 5 letters, the probability of choosing any specific letter is 1 out of 5, or 20%. If you're looking for the probability of choosing a vowel (a or e), it would be 2 out of 5, or 40%.
To determine the probability of the spinner landing on B and then C, we need to know the individual probabilities of landing on B and C. Assuming the spinner is fair and has an equal number of sections for A, B, and C, the probability of landing on B is 1/3, and the probability of landing on C is also 1/3. Thus, the combined probability of landing on B first and then C is (1/3) * (1/3) = 1/9.
The probability is 2/11.
The Probability of NOT reading newspaper a is .8 The Probability of NOT reading Newspaper b is .84 The probability of NOT reading Newspaper c is .86 Therefore, .8*.84*.86=0.57792=57.792%
50 %
Since the word "probability" contains only letters, then the probability of choosing a letter from the word "probability" is 1, i.e. it is certain to happen.
The word "space" consists of 5 letters: s, p, a, c, and e. If you are choosing one letter at random from these 5 letters, the probability of choosing any specific letter is 1 out of 5, or 20%. If you're looking for the probability of choosing a vowel (a or e), it would be 2 out of 5, or 40%.
To determine the probability of the spinner landing on B and then C, we need to know the individual probabilities of landing on B and C. Assuming the spinner is fair and has an equal number of sections for A, B, and C, the probability of landing on B is 1/3, and the probability of landing on C is also 1/3. Thus, the combined probability of landing on B first and then C is (1/3) * (1/3) = 1/9.
2/11
The probability is 2/11.
The Probability of NOT reading newspaper a is .8 The Probability of NOT reading Newspaper b is .84 The probability of NOT reading Newspaper c is .86 Therefore, .8*.84*.86=0.57792=57.792%
the probability would be 1/3
50 %
b is incorrect while c is virtually meaningless.
the probability is 3/12 or 1/4
The probability is 21/26.
The probability is 2:7.