The total number of alphabets is 26. So the probability of letter C = No of time c is present in the alphabets / Total number of alphabets So probability of letter c is 1/26
No
C=cost x=cans C=70x
int matrix[][]; // the matrix to find the max in int max = matrix[0][0]; int r,c; for(r = 0; r < 3; ++r) { for(c = 0; c < 3; ++c) { if(matrix[r][c] > max) { max = matrix[r][c]; } } } // max is now the maximum number in matrix
First the 'values' of the GPA system:A = 4 pointsB = 3 pointsC = 2 pointsD = 1 pointF = 0 pointsSo, add the sum of the points and divide by the total number of entries. So In this particular question: 3 x 2 = 6 (for the 3 C's) + 4 + 3 + 1 + 0.So ... 6+4+3+1+0 = 14. Now divide that by the total entries (7) and you get 2, or a C grade average.
C-3
The oxidation number of C in CāOā is +3. Each oxygen atom carries a charge of -2, and since there are 4 oxygen atoms in total with a total charge of -8, the carbon atom's oxidation number must be +3 to balance the charges in the compound.
The oxidation number of C in C2O4^2- is +3. This is because each O atom is assigned an oxidation number of -2, and the overall charge of the ion is -2, so the two C atoms must have a total oxidation number of +6 in order to balance the charge.
The answer is this: c/5=3 c=15
The total number of alphabets is 26. So the probability of letter C = No of time c is present in the alphabets / Total number of alphabets So probability of letter c is 1/26
The oxidation number of carbon (C) in Al4C3 is -4. This is because aluminum (Al) has an oxidation number of +3 and there are 4 aluminum atoms for a total oxidation number of +12. This must be balanced by the oxidation numbers of the carbon atoms, which must be -4 in order for the compound to be neutral.
No
Total students in class = C Number of boys = Z Number of girls = C-Z Total stamps distributed = (3xZ) + [(C-Z)x5] = 3Z + 5C - 5Z = 5C - 2Z
there is 8 Na-1 C-2 H-3 O-2
5 atoms totally: 1 lithium (Li), 1 carbon (C) and 3 oxygen (O)
Well, let's think about this in a happy little way. In a mixture of substances B and C, the total number of molecules will be the sum of the molecules in B and C. Each substance brings its own molecules to the mix, creating a beautiful blend of different molecules dancing together. So, the number of molecules in the mixture will be the total from B and C, creating a harmonious union.
C=cost x=cans C=70x