the adjacent side over the hypotenuse
cos(270) = 0
Sin= Opposite leg/Hypotenuse Cos= Adjacent leg/ Hypotenuse Tan=Adjacent leg/ Opposite leg
sin = sqrt(1 - cos^2)tan = sqrt(1 - cos^2)/cossec = 1/coscosec = 1/sqrt(1 - cos^2)cot = cos/sqrt(1 - cos^2)
We use the dot product cos and in vector we use the vector product sin because of the trigonometric triangle.
In math, the sine and cosine functions are one of the main trigonometric functions. All other trigonometric function can be specified within the expressions of them. The sine and cosine functions are exactly related and can be articulated within conditions of every other. Let us consider A be the angle sine can be identified as the ratio of the side opposite near to the angle toward the hypotenuse. Cosine of an angle is the ratio of the side adjacent to the angle A to the hypotenuse.
cos(22) is a trigonometric ratio and, if the angle is measured in degrees, its value is 0.9272
cos(22) is a trigonometric ratio and, if the angle is measured in degrees, its value is 0.9272
cos(22) is a trigonometric ratio and, if the angle is measured in degrees, its value is 0.9272
cos(270) = 0
Sin= Opposite leg/Hypotenuse Cos= Adjacent leg/ Hypotenuse Tan=Adjacent leg/ Opposite leg
sin, cos and tan
For a right angle triangle the trigonometrical ration is: tangent = opposite/adjacent
opposite over adjacent
sin = sqrt(1 - cos^2)tan = sqrt(1 - cos^2)/cossec = 1/coscosec = 1/sqrt(1 - cos^2)cot = cos/sqrt(1 - cos^2)
"COS" stands for "Cosine", which is one of the 6 trigonometric functions. Similarly, "SIN" stands for Sine, and TAN stands for Tangent.
Thanks to the pre-existing addition and subtraction theorums, we can establish the identity:sin(a+b) = sin(a)cos(b)+sin(a)cos(b)Then, solving this, we getsin(a+b) = 2(sin(a)cos(b))sin(a)cos(b) = sin(a+b)/2a=b, sosin(a)cos(a) = sin(a+a)/2sin(a)cos(a) = sin(2a)/2Therefore, the answer is sin(2a)/2.
We use the dot product cos and in vector we use the vector product sin because of the trigonometric triangle.