cos(270) = 0
Sin= Opposite leg/Hypotenuse Cos= Adjacent leg/ Hypotenuse Tan=Adjacent leg/ Opposite leg
sin = sqrt(1 - cos^2)tan = sqrt(1 - cos^2)/cossec = 1/coscosec = 1/sqrt(1 - cos^2)cot = cos/sqrt(1 - cos^2)
We use the dot product cos and in vector we use the vector product sin because of the trigonometric triangle.
sin(3A) = sin(2A + A) = sin(2A)*cos(A) + cos(2A)*sin(A)= sin(A+A)*cos(A) + cos(A+A)*sin(A) = 2*sin(A)*cos(A)*cos(A) + {cos^2(A) - sin^2(A)}*sin(A) = 2*sin(A)*cos^2(A) + sin(a)*cos^2(A) - sin^3(A) = 3*sin(A)*cos^2(A) - sin^3(A)
cos(22) is a trigonometric ratio and, if the angle is measured in degrees, its value is 0.9272
cos(22) is a trigonometric ratio and, if the angle is measured in degrees, its value is 0.9272
cos(270) = 0
Sin= Opposite leg/Hypotenuse Cos= Adjacent leg/ Hypotenuse Tan=Adjacent leg/ Opposite leg
sin, cos and tan
For a right angle triangle the trigonometrical ration is: tangent = opposite/adjacent
In physics, cosine function is used to determine the x-component of a vector. So cos(22) in physics would give you the x-component of a vector that makes an angle of 22 degrees with the positive x-axis.
opposite over adjacent
sin = sqrt(1 - cos^2)tan = sqrt(1 - cos^2)/cossec = 1/coscosec = 1/sqrt(1 - cos^2)cot = cos/sqrt(1 - cos^2)
"COS" stands for "Cosine", which is one of the 6 trigonometric functions. Similarly, "SIN" stands for Sine, and TAN stands for Tangent.
Thanks to the pre-existing addition and subtraction theorums, we can establish the identity:sin(a+b) = sin(a)cos(b)+sin(a)cos(b)Then, solving this, we getsin(a+b) = 2(sin(a)cos(b))sin(a)cos(b) = sin(a+b)/2a=b, sosin(a)cos(a) = sin(a+a)/2sin(a)cos(a) = sin(2a)/2Therefore, the answer is sin(2a)/2.
We use the dot product cos and in vector we use the vector product sin because of the trigonometric triangle.