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3 to a power divisible by 4 will have a units digit of 1.The powers of 3 are 3, 9, 27, 81 ... obviously, the next one will have a units digit of 1x3 or 3, the next one will have a units digit of 3x3 or 9, the next one will have a units digit of 7 (because 9x3 is 27), the next one will have a units digit of 1 (because 7x3 is 21), and then the cycle starts over with a units digit of 3 again.
27th.
33 = 27 cubic units
October 27, 1976 fell on a Wednesday.
To solve a question like this, one looks at patterns of powers. For example: 31 = 3 32 = 9 33 = 27 34 = 81 Hence 34 = 1 and 38 = 1 and 312 = 1 and 316 = 1 and so on ............ now in this same sequence 3200 = 1 hence unit digit is 1.
3 to a power divisible by 4 will have a units digit of 1.The powers of 3 are 3, 9, 27, 81 ... obviously, the next one will have a units digit of 1x3 or 3, the next one will have a units digit of 3x3 or 9, the next one will have a units digit of 7 (because 9x3 is 27), the next one will have a units digit of 1 (because 7x3 is 21), and then the cycle starts over with a units digit of 3 again.
10 to the negative 27th power (10-27) equals 0.000000000000000000000000001
10^27 or 10 to the 27th power
it would be 3 with 27 zero's. In the US it would be known as an octillion. 300,000,000,000,000,000,000,000,000
The math equation of the number 10 to the 27th power can be simplified as saying the number 10 times itself (10x10) twenty seven times. So the 27th power is how many times the original number multiplies its self.
It is two multiplied by itself 27 times. I leave the actual numerical amount as an exercise for the student.
27. Let the first (tens) digit be x. Then, since the units digit is the tens digit plus 5, the second (units) digit is (x + 5) and the number is: 10x + (x + 5) = 11x + 5. And 3 times the sums of its digits is: 3(x + (x + 5)) = 3(2x + 5) = 6x + 15 But this is equal to the number, so: 11x + 5 = 6x + 15 ⇒ 5x = 10 ⇒ x = 2 ⇒ (x + 5) = (2 + 5) = 7 So the number is 27. Checking: 3 x (2 + 7) = 3 x 9 = 27
27th
27th.
The value of the ones digit in 27 is 7.
January 27 is the 27th day of the year and 34 days after Christmas.
seven tenths