3 to a power divisible by 4 will have a units digit of 1.The powers of 3 are 3, 9, 27, 81 ... obviously, the next one will have a units digit of 1x3 or 3, the next one will have a units digit of 3x3 or 9, the next one will have a units digit of 7 (because 9x3 is 27), the next one will have a units digit of 1 (because 7x3 is 21), and then the cycle starts over with a units digit of 3 again.
To find the units digit of 3 to the 200th power, we need to observe the pattern of units digits as we raise 3 to higher powers. The units digit of 3 to any power follows a repeating cycle: 3, 9, 7, 1. Since the cycle has a length of 4, we can divide 200 by 4 to find the remainder. 200 divided by 4 gives a remainder of 0, meaning the units digit of 3 to the 200th power is the last digit in the cycle, which is 1.
27th.
October 27, 1976 fell on a Wednesday.
33 = 27 cubic units
3 to a power divisible by 4 will have a units digit of 1.The powers of 3 are 3, 9, 27, 81 ... obviously, the next one will have a units digit of 1x3 or 3, the next one will have a units digit of 3x3 or 9, the next one will have a units digit of 7 (because 9x3 is 27), the next one will have a units digit of 1 (because 7x3 is 21), and then the cycle starts over with a units digit of 3 again.
10 to the negative 27th power (10-27) equals 0.000000000000000000000000001
10^27 or 10 to the 27th power
To find the units digit of 3 to the 200th power, we need to observe the pattern of units digits as we raise 3 to higher powers. The units digit of 3 to any power follows a repeating cycle: 3, 9, 7, 1. Since the cycle has a length of 4, we can divide 200 by 4 to find the remainder. 200 divided by 4 gives a remainder of 0, meaning the units digit of 3 to the 200th power is the last digit in the cycle, which is 1.
it would be 3 with 27 zero's. In the US it would be known as an octillion. 300,000,000,000,000,000,000,000,000
The math equation of the number 10 to the 27th power can be simplified as saying the number 10 times itself (10x10) twenty seven times. So the 27th power is how many times the original number multiplies its self.
It is two multiplied by itself 27 times. I leave the actual numerical amount as an exercise for the student.
27. Let the first (tens) digit be x. Then, since the units digit is the tens digit plus 5, the second (units) digit is (x + 5) and the number is: 10x + (x + 5) = 11x + 5. And 3 times the sums of its digits is: 3(x + (x + 5)) = 3(2x + 5) = 6x + 15 But this is equal to the number, so: 11x + 5 = 6x + 15 ⇒ 5x = 10 ⇒ x = 2 ⇒ (x + 5) = (2 + 5) = 7 So the number is 27. Checking: 3 x (2 + 7) = 3 x 9 = 27
27th
27th.
The value of the ones digit in 27 is 7.
January 27 is the 27th day of the year and 34 days after Christmas.