To find the units digit of (27^{27}), we can look at the units digit of (27), which is (7). We then need to find the units digit of (7^{27}). The units digits of the powers of (7) cycle every four terms: (7^1 = 7), (7^2 = 49) (units digit (9)), (7^3 = 343) (units digit (3)), and (7^4 = 2401) (units digit (1)). Since (27 \mod 4 = 3), the units digit of (7^{27}) is the same as that of (7^3), which is (3). Thus, the units digit of (27^{27}) is (3).
Well, honey, to find the unit digit of 3 to the 60th power, you just need to look for a pattern. The unit digits of powers of 3 repeat every 4 powers, so you divide 60 by 4, which gives you a remainder of 0. Therefore, the unit digit of 3 to the 60th power is 1.
The units digit of 3 raised to any power follows a pattern: 3, 9, 7, 1, and then it repeats. Since 200 is divisible by 4, the units digit of 3 to the 200th power is 1. So, grab a calculator or trust my sassy math skills, honey, the answer is 1.
27th.
33 = 27 cubic units
October 27, 1976 fell on a Wednesday.
10^27 or 10 to the 27th power
10 to the negative 27th power is equal to 1 divided by 10 raised to the 27th power. This can be simplified to 1 divided by 10,000,000,000,000,000,000,000,000,000, which is equal to 0.0000000000000000000000000001. In scientific notation, this number would be written as 1 x 10^-27.
Well, honey, to find the unit digit of 3 to the 60th power, you just need to look for a pattern. The unit digits of powers of 3 repeat every 4 powers, so you divide 60 by 4, which gives you a remainder of 0. Therefore, the unit digit of 3 to the 60th power is 1.
The units digit of 3 raised to any power follows a pattern: 3, 9, 7, 1, and then it repeats. Since 200 is divisible by 4, the units digit of 3 to the 200th power is 1. So, grab a calculator or trust my sassy math skills, honey, the answer is 1.
it would be 3 with 27 zero's. In the US it would be known as an octillion. 300,000,000,000,000,000,000,000,000
The math equation of the number 10 to the 27th power can be simplified as saying the number 10 times itself (10x10) twenty seven times. So the 27th power is how many times the original number multiplies its self.
It is two multiplied by itself 27 times. I leave the actual numerical amount as an exercise for the student.
27. Let the first (tens) digit be x. Then, since the units digit is the tens digit plus 5, the second (units) digit is (x + 5) and the number is: 10x + (x + 5) = 11x + 5. And 3 times the sums of its digits is: 3(x + (x + 5)) = 3(2x + 5) = 6x + 15 But this is equal to the number, so: 11x + 5 = 6x + 15 ⇒ 5x = 10 ⇒ x = 2 ⇒ (x + 5) = (2 + 5) = 7 So the number is 27. Checking: 3 x (2 + 7) = 3 x 9 = 27
27th
27th.
The value of the ones digit in 27 is 7.
January 27 is the 27th day of the year and 34 days after Christmas.