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27.

Let the first (tens) digit be x. Then, since the units digit is the tens digit plus 5, the second (units) digit is (x + 5) and the number is:

10x + (x + 5) = 11x + 5.

And 3 times the sums of its digits is:

3(x + (x + 5)) = 3(2x + 5)

= 6x + 15

But this is equal to the number, so:

11x + 5 = 6x + 15

⇒ 5x = 10

⇒ x = 2

⇒ (x + 5) = (2 + 5) = 7

So the number is 27.

Checking: 3 x (2 + 7) = 3 x 9 = 27

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Q: What is the two digit numeral whose units' digit is 5 more than its tens digit and whose value equals 3 times the sum of these digits?
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