x2-2x = 63
x2-2x -63 = 0 => x = -7 or x = 9
So x must = 9
Check: 92-18 = 63
No, it is the discriminant of a quadratic equation.
No, not if the y is squared. When graphed the equation will not form a straight line.
The equation ax2 + bx + c = 0, where a != 0 is called quadratic.
Because it is in the form of ax^2+bx+c=0 Because quadratic means squared hence ax squared + bx +c=0 has a squared number as it's highest term. This is in fact the area of a square of a side "x" is x^2, so every equation having variable with exponent 2 become quadratic equation.
expanded form
No, it is the discriminant of a quadratic equation.
No, not if the y is squared. When graphed the equation will not form a straight line.
It is 22*54 = 2500.
First, you remove every x that you can from the equation. Next, you reach the simplest form of the equation, which is (7x-2)(x-2). Which is the lowest factorable form.
The equation ax2 + bx + c = 0, where a != 0 is called quadratic.
Because it is in the form of ax^2+bx+c=0 Because quadratic means squared hence ax squared + bx +c=0 has a squared number as it's highest term. This is in fact the area of a square of a side "x" is x^2, so every equation having variable with exponent 2 become quadratic equation.
For a horizontal line, it is y= a value
In the equation y x-5 2 plus 16 the standard form of the equation is 13. You find the answer to this by finding the value of X.
The value obtained when an equation is used to calculate the amount of product that will form during a reaction is called THE THEORETICAL YIELD.
expanded form
An equation of the second degree, meaning it contains at least one term that is squared.
1st rearrange the equation so that it is in the form Y = . . . . .Then substitute in values for X (use whole numbers) and use the equation to calculate the value of Y (not Y squared).Then plot these numbers against each other (X and Y) on your graph.Remember that you also need to include negative values for X and when taking a square root the answer can be plus or minus (plot both), if you do enough examples you'll see a pattern forming