Without any equality signs the given terms can't be considered to be equations.
There is only one equation, so it's not a system of equations.
2x+3y = 6 2x+3(0) = 6 2x = 6 x = 6/2 x = 3
y = 4x-8 and y = 2x+10 4x-8 = 2x+10 4x-2x = 10+8 2x = 18 x = 9 Substitute the value of x into the original equations to find the value of y: Therefore: x = 9 and y = 28
Inconsistent linear equations in two variables.
x = 4 and y = 0
How many solutions are there to the following system of equations?2x - y = 2-x + 5y = 3if this is your question,there is ONLY 1 way to solve it.
None because the given terms of an expression are not equations because there are no equality signs.
To find the value of ( x ), we can set up an equation using the given relationships. From the equations: ( ad = x ) ( ab = 2x - 2 ) ( ae = x + 2 ) ( ac = 2x + 1 ) Assuming these represent lengths that relate in a triangle or geometric figure, we can analyze them together. Matching the equations appropriately or checking for consistency often leads to the right value. Solving the system, we find that ( x = 2 ).
x = 1 and y = 2
If you mean 3x+2y = -5 and -2x+3y = -5 then they are straight line equations
The equations are identical in value, ie the second is merely twice the first...
They are parallel.