when x = 2
it equals 28
-14
6x plus 3 equals 8x plus 14 when solved mathematically is equal to x = -5.5.
x-2y=14 x+3y =9 subtract the equations x-2y = 14 -x-3y = -9 -5y = 5 divie both sides by -5 y = -1 substitute y = -1 into the first equation (or second) x -2(-1) = 14 x + 2 = 14 x = 12
when x = 2
The equations are identical in value, ie the second is merely twice the first...
why will the equations x+14=37 and x-14=37 have different solutions for x
It is not possible to solve one equation in two unknowns (x and y). Two independent equations are required.
it equals 28
4x - y = 1 3x + y = 13 Add the equations: 7x = 14 so that x = 2 and then, by the first equations, 4*2 - y= 1 so that y = 7
14 + 14 = 28
-14
6x plus 3 equals 8x plus 14 when solved mathematically is equal to x = -5.5.
x-2y=14 x+3y =9 subtract the equations x-2y = 14 -x-3y = -9 -5y = 5 divie both sides by -5 y = -1 substitute y = -1 into the first equation (or second) x -2(-1) = 14 x + 2 = 14 x = 12
7x+4y = 39 2x+4y = 14 Subtract the equations in order to eliminate y: 5x = 25 Divide both sides by 5 to find the value of x: x = 5 Substitute the value of x into the original equations to find the value of y: Therefore: x = 5 and y = 1
13...... 9 plus 5 equals 14...... 14 minus 1 equals 13