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Best Answer

Y = X^2 + 10X + 22

set to 0

X^2 + 10X + 22 = 0

subtract 22 from both sides

X^2 + 10X = - 22

Now, complete the square by halving the linear term (10), squaring it and adding it to both sides

X^2 + 10X + 25 = - 22 + 25

factor the left side, gather terms right side

(X + 5)^2 = 3

(X + 5)^2 - 3 = 0

(-5,-3)

-------------------the vertx

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13y ago
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Q: What is the vertex y equals x2 plus 10 plus 22?
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