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First, a closed circuit would not have any voltage across the circuit. As going around the whole circuit, the sum of the voltage drops equals zero. However, you can measure the voltage drop across this particular part of the circuit (a 700 kΩ
resistor - probably a spark gap or insulation that broke down and arced through).
Use Ohm's Law: V = IR (voltage = current times resistance). Note that in normal circuits, you won't have such a high current combined with such a high resistance (the power dissipation in this case would be 17.5 MW!) Perhaps the current was supposed to be in milli-ampere instead of ampere. Anyway for the 700 kiloohm resistance it is 3,500,000 Volts (3.5 Megavolts)
What else can I help you with?
The sum of the voltage drops around a series circuit is the voltage source input.?
Yes, in a series circuit, the sum of the voltage drops across each component equals the total voltage supplied by the voltage source. This principle is a manifestation of Kirchhoff's Voltage Law, which states that the total voltage around a closed loop must equal zero. Therefore, the voltage provided by the source must equal the combined voltage drops across all components in the circuit.
The applied voltage in a circuit equals the sum of the circuits individual what?
For a series circuit, the applied voltage equals the sum of the voltage drops
Is there a relationship between the sums and the electrical potential across the source?
Yes, there is a relationship between the sums of electrical potential differences in a circuit and the electrical potential across the source. The sum of the potential differences around a closed loop in a circuit equals zero, known as Kirchhoff's Voltage Law. This means that the sum of the potential drops across circuit elements is equal to the potential rise across the power source.
How to determine amp draw in an electrical circuit?
To determine amp draw in an electrical circuit, you can use Ohm's Law, which states that current (amps) equals voltage divided by resistance. Measure the voltage across the circuit and the resistance of the components in the circuit, then divide the voltage by the resistance to calculate the amp draw.
Using ohm's law what is the formula to find the resistance in a circuit?
Resistance of the circuit = (voltage across the circuit) divided by (current through the circuit)
How do you calculate electrical power?
Voltage x current. In a resistor for example it is the voltage drop across it that is relevant, it may be part of a circuit.
What is the total voltage drop across a set of resistors in series?
Simply add all of the component's resistances together and that will give you circuits total resistance. If you're dealing with a 'series-parallel', or 'parallel' circuit, the equations will change, but in a simple series circuit, the total resistance is just the total of all the component's resistance.
Verification of kvl and voltage divider rule with answer conkulasion?
Kirchhoff's Voltage Law (KVL) states that the sum of the electrical potential differences (voltages) around any closed circuit loop must equal zero. To verify KVL, one can measure the voltages across each component in a loop and confirm that their sum equals the total supply voltage. The voltage divider rule, which states that the voltage across a resistor in a series circuit is a fraction of the total voltage based on the resistor's value relative to the total resistance, can be validated by calculating the expected voltages and measuring them. In conclusion, both KVL and the voltage divider rule can be experimentally verified, demonstrating the consistency of circuit analysis principles.
How will be phasor diagram if XL equals XC?
When the inductive reactance (XL) equals the capacitive reactance (XC) in an AC circuit, the circuit is said to be in resonance. In a phasor diagram, the voltage phasor across the inductor (V_L) and the voltage phasor across the capacitor (V_C) will be equal in magnitude but opposite in direction, effectively canceling each other out. As a result, the total voltage phasor will be aligned with the current phasor, indicating that the circuit behaves as purely resistive at this point. The current phasor will lead the voltage phasor by 90 degrees in an inductive circuit and lag in a capacitive circuit, but at resonance, they are in phase.
In a series circuit voltage drop across each resistance (load) will?
In a series circuit, the voltage drop across each resistor is proportional to its resistance value according to Ohm's Law (V = IR). The total voltage supplied by the source is divided among the resistors, so the sum of the individual voltage drops equals the total voltage. As a result, resistors with higher resistance will have a larger voltage drop compared to those with lower resistance.
What is the Condition for terminal voltage across a secondary cell to be equal to its emf?
The condition for the terminal voltage across a secondary cell to be equal to its emf is when there is no current flowing through the cell. When there is no current, there is no voltage drop across the internal resistance of the cell, and thus the terminal voltage equals the emf.
How do voltage and current and restistance all link together?
According to ohm's law, voltage in a circuit is directly proportional to current in the circuit and when that proportionality sign is taken off to equals to, a constant is introduced with current and is called resistance. Therefore Voltage in a circuit equals to product of current and resistance in that circuit.
